sevensnight

2025年3月11日

摘要：环(Ring) 环是一个集合RR,配备两种二元运算(加法+和乘法×),满足: 加法构成阿贝尔群(交换律、结合律、存在零元、逆元) 乘法满足结合律,且对加法有分配律例子:整数集ZZ,实数集RR,矩阵环Mn(R) 环的定义比群(Group)更复杂,因为它涉及两种运算,但比域(Field)更一般,因为环阅读全文

posted @ 2025-03-11 21:52 sevensnight 阅读(73) 评论(0) 推荐(0)

证书修复

摘要：题目: #break.pem BEGIN BREAK PEM PRIVATE MIIEowIBAAKCAQEAw6JUixKmoIZjLyR1Qc/D/3mfTC3YvqKienLM7Nt/83UqpYeg 9rOw02xLtIqgBdVyVkI+MknQdB5tB1W/bo95M8JjmNxi5r 阅读全文

posted @ 2025-03-11 21:46 sevensnight 阅读(151) 评论(0) 推荐(0)

证书格式

摘要： RSA_PKCS#1私钥解密题目: #私钥 BEGIN RSA PRIVATE KEY MIIEvQIBADANBgkqhkiG9w0BAQEFAASCBKcwggSjAgEAAoIBAQDLzJrQLXi4OjFl Yr5EAfQHWnF0ZyZsHHGfNNRLlhL1haAbV2AzTQCC 阅读全文

posted @ 2025-03-11 21:46 sevensnight 阅读(61) 评论(0) 推荐(0)

求解多项式GCD(共e)(Half-GCD算法)

摘要：题目: from Crypto.Util.number import * from secret import flag m = bytes_to_long(flag) p1, q1 = getPrime(512), getPrime(512) n1 = p1*q1 e = 65537 p2, q2 阅读全文

posted @ 2025-03-11 21:46 sevensnight 阅读(124) 评论(0) 推荐(0)

AMM算法进阶

摘要：题目: from Crypto.Util.number import * import os from gmpy2 import * def getMyPrime1(nbits): while True: n = 2*1009*7*getPrime(nbits//2)*getPrime(nbits/ 阅读全文

posted @ 2025-03-11 21:45 sevensnight 阅读(48) 评论(0) 推荐(0)

AMM算法

摘要：题目: from Crypto.Util.number import * import os from gmpy2 import * def getMyPrime(nbits): while True: n = 2*1009*getPrime(nbits//2)*getPrime(nbits//2) 阅读全文

posted @ 2025-03-11 21:45 sevensnight 阅读(72) 评论(0) 推荐(0)

共模攻击进阶

摘要：题目: from Crypto.Util.number import * p = getPrime(700) q = getPrime(700) n = p*q e1 = 3*getPrime(16) e2 = 3*getPrime(16) flag = b'NSSCTF{******}' c1 = 阅读全文

posted @ 2025-03-11 21:45 sevensnight 阅读(35) 评论(0) 推荐(0)

限定范围的p+1

摘要：题目: from Crypto.Util.number import * import random primes = [] for i in range(1000): primes.append(getPrime(64)) def getMyPrime(nbits: int): while Tru 阅读全文

posted @ 2025-03-11 21:45 sevensnight 阅读(24) 评论(0) 推荐(0)

限定范围的p-1

摘要：题目: from Crypto.Util.number import * import random primes = [] for i in range(1000): primes.append(getPrime(64)) def getMyPrime(nbits: int): while Tru 阅读全文

posted @ 2025-03-11 21:45 sevensnight 阅读(15) 评论(0) 推荐(0)

广播攻击-CRT不互素?

摘要：题目: from Crypto.Util.number import * from gmpy2 import * import random flag = b'******' flag = bytes_to_long(flag) nl = [] cl = [] def getn(bits): n = 阅读全文

posted @ 2025-03-11 21:45 sevensnight 阅读(53) 评论(0) 推荐(0)

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