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摘要: 题目: from Crypto.Util.number import * import gmpy2 flag = b'NSSCTF{******}' p = getPrime(512) q = gmpy2.next_prime(p) n = p*q e = 65537 phi = (p-1)*(q- 阅读全文
posted @ 2025-03-11 14:00 sevensnight 阅读(21) 评论(0) 推荐(0)
摘要: 题目: from Crypto.Util.number import * flag = b'NSSCTF{******}' p = getPrime(256) q = getPrime(256) n = p*q e = 65537 phi = (p-1)*(q-1) m = bytes_to_lon 阅读全文
posted @ 2025-03-11 13:59 sevensnight 阅读(23) 评论(0) 推荐(0)
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