sevensnight

2025年3月11日

摘要：题目1: from Crypto.Util.number import * p = getPrime(512) q = getPrime(512) n = p*q e = 65537 m = bytes_to_long(b"nbctf{[REDACTED]}") ct = pow(m,e,n) pr 阅读全文

posted @ 2025-03-11 22:06 sevensnight 阅读(52) 评论(0) 推荐(0)

已知p部分高位部分低位攻击

摘要：题目: from Crypto.Util.number import getPrime, bytes_to_long from secret import flag p = getPrime(1024) q = getPrime(1024) n = p * q e = 65537 hint1 = p 阅读全文

posted @ 2025-03-11 22:05 sevensnight 阅读(79) 评论(0) 推荐(0)

已知p高位攻击(在模p下的类型)(位数不变)

摘要：题目: from Crypto.Util.number import * from gmpy2 import * from tqdm import * # flag = b'ZLCTF{记得那年的雨季，回忆里特安静，哭过后的决定，是否还能进行}' m = bytes_to_long(flag) p 阅读全文

posted @ 2025-03-11 22:05 sevensnight 阅读(13) 评论(0) 推荐(0)

已知p高位攻击

摘要：题目: from Crypto.Util.number import * p = getPrime(512) q = getPrime(512) flag = b'NSSCTF{******}' n = p*q m = bytes_to_long(flag) e = 65537 c = pow(m, 阅读全文

posted @ 2025-03-11 22:05 sevensnight 阅读(18) 评论(0) 推荐(0)

已知m高位攻击(位数不变)

摘要：题目: from Crypto.Util.number import getPrime,bytes_to_long,long_to_bytes from random import randint from secret import flag p = getPrime(1024) q = getP 阅读全文

posted @ 2025-03-11 22:05 sevensnight 阅读(22) 评论(0) 推荐(0)

已知m高位攻击

摘要：题目: from Crypto.Util.number import * p = getPrime(512) q = getPrime(512) flag = b'NSSCTF{******}' n = p*q m = bytes_to_long(flag) e = 3 c = pow(m, e, 阅读全文

posted @ 2025-03-11 22:05 sevensnight 阅读(48) 评论(0) 推荐(0)

已知m低位(可以看作短填充)

摘要：题目: from Crypto.Util.number import * from secret import flag p = getPrime(512) q = getPrime(512) assert GCD(3, (p-1)*(q-1)) != 1 assert len(flag) == 4 阅读全文

posted @ 2025-03-11 22:05 sevensnight 阅读(16) 评论(0) 推荐(0)

SMUPE扩展进阶

摘要：题目: import random from Crypto.Util.number import * m = bytes_to_long(b'NSSCTF{******}') e = [3, 3, 5, 5, 5] cnt = 5 A = [random.randint(1, 128) for i 阅读全文

posted @ 2025-03-11 22:04 sevensnight 阅读(32) 评论(0) 推荐(0)

SMUPE扩展

摘要：题目: import random from Crypto.Util.number import * m = bytes_to_long(b'NSSCTF{******}') e = 3 cnt = 5 A = [random.randint(1, 128) for i in range(cnt)] 阅读全文

posted @ 2025-03-11 22:04 sevensnight 阅读(6) 评论(0) 推荐(0)

线性填充广播攻击

摘要：题目: from Crypto.Util.number import * flag = b'NSSCTF{******}' p = getPrime(700) q = getPrime(700) n = p*q e = 5 m1 = bytes_to_long(flag) a = getPrime( 阅读全文

posted @ 2025-03-11 22:04 sevensnight 阅读(16) 评论(0) 推荐(0)

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