python用海伦公式计算三角形阴影面积
def sjx(a,b,c):
p=(a+b+c)/2
x=(p*(p-a)*(p-b)*(p-c))**0.5
return x
s1=sjx(9.8,9.3,6.4)
s2=sjx(2.9,4.1,4.7)
s3=sjx(2.0,1.4,2.3)
print(s1-s2+s3)
def sjx(a,b,c):
p=(a+b+c)/2
x=(p*(p-a)*(p-b)*(p-c))**0.5
return x
s1=sjx(9.8,9.3,6.4)
s2=sjx(2.9,4.1,4.7)
s3=sjx(2.0,1.4,2.3)
print(s1-s2+s3)