python用海伦公式计算三角形阴影面积
def sjx(a,b,c): p=(a+b+c)/2 x=(p*(p-a)*(p-b)*(p-c))**0.5 return x s1=sjx(9.8,9.3,6.4) s2=sjx(2.9,4.1,4.7) s3=sjx(2.0,1.4,2.3) print(s1-s2+s3)
def sjx(a,b,c): p=(a+b+c)/2 x=(p*(p-a)*(p-b)*(p-c))**0.5 return x s1=sjx(9.8,9.3,6.4) s2=sjx(2.9,4.1,4.7) s3=sjx(2.0,1.4,2.3) print(s1-s2+s3)