在Asp.net webform中，如何找出哪一个按钮触发Button PostBack事件。先看ASPX：
1: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
2: <html xmlns="http://www.w3.org/1999/xhtml">
3: <head runat="server">
4: <title>Petter Liu demo</title>
5: 6: <script src="http://ajax.microsoft.com/ajax/jquery/jquery-1.4.2.min.js" type="text/javascript"></script>
7: 8: <script type="text/javascript">
9: $(function() {
10: $("input:submit").click(function() {
11: $("#HiddenField1").val($(this).attr("id")
12: + " 引起一个 postback");
13: }); 14: }); 15: </script>
16: 17: </head>
18: <body>
19: <form id="form1" runat="server">
20: <div>
21: <asp:Button ID="Button1" runat="server" Text="Button1" />
22: <asp:Button ID="Button2" runat="server" Text="Button2" />
23: <asp:Button ID="Button3" runat="server" Text="Button3" />
24: <asp:HiddenField ID="HiddenField1" runat="server" />
25: </div>
26: </form>
27: </body>
28: </html>
然后在Sever端这么写：
1: /// <summary>
2: /// Handles the Load event of the Page control.
3: /// </summary>
4: /// <param name="sender">The source of the event.</param>
5: /// <param name="e">The <see cref="System.EventArgs"/> instance containing the event data.</param>
6: /// <remarks>Author Petter Liu http://wintersun.cnblogs.com </remarks>
7: protected void Page_Load(object sender, EventArgs e)
8: { 9: Response.Write(HiddenField1.Value); 10: }很简单的CODE.
希望这篇POST对您有帮助。
作者：Petter Liu
出处：http://www.cnblogs.com/wintersun/
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该文章也同时发布在我的独立博客中-Petter Liu Blog。
