摘要:
简单题,主要考察索引计算和字符遍历,没什么难度; vector<vector<int>> largeGroupPositions(string s) { vector<vector<int>> res; for (size_t i = 0; i < s.size();) { size_t index 阅读全文
摘要:
简单题,没什么好说的,Hash数组+两次遍历可破; int firstUniqChar(string s) { for (int i = 0; i < s.size(); i++) { hashtable[s[i] - 'a']++; } int index = 0; for (int i = 0; 阅读全文