Given an integer array nums
, return the length of the longest strictly increasing .
Example 1:
Input: nums = [10,9,2,5,3,7,101,18] Output: 4 Explanation: The longest increasing subsequence is [2,3,7,101], therefore the length is 4.
Example 2:
Input: nums = [0,1,0,3,2,3] Output: 4
Example 3:
Input: nums = [7,7,7,7,7,7,7] Output: 1
Constraints:
1 <= nums.length <= 2500
-104 <= nums[i] <= 104
My Solution:
class Solution: def lengthOfLIS(self, nums: List[int]) -> int: n = len(nums) if n == 1: return 1 # LIS[k] = LIS ending at index k # LIS[n] = 1 + max{LIS[k] | k < n, nums[k] < nums[n]} LIS = [1] * n for i in range(1, n): subproblems = [LIS[k] for k in range(i) if nums[k] < nums[i]] LIS[i] = 1 + max(subproblems, default=0) return max(LIS)