摘要:
代码实现: public int maxSubArray(int[] nums) { int[] dp = new int[nums.length]; dp[0] = nums[0]; int max = nums[0]; for (int i = 1; i < nums.length; i++) 阅读全文
摘要:
解法一: 序列dp class Solution { int count[]= new int[10001]; public int deleteAndEarn(int[] nums) { int max =0; int n=nums.length; if(n==0) return 0; for ( 阅读全文