每日一题-区间分组
摘要:
区间分组 sort(a.begin(), a.end()); priority_queue<int, vector<int>, greater<int>> q; for (int i = 0; i < n; ++i) { if (q.empty() or q.top() >= a[i].first) 阅读全文
posted @ 2022-11-09 21:52 Whosedream-0019 阅读(42) 评论(0) 推荐(0)
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