每日一题-区间覆盖
摘要:
区间覆盖 sort(a.begin(), a.end()); int ans = 0, las = s; for (int i = 0; i < n; ++i) { int j = i; int r = -2e9; while (j < n and a[j].first <= las) { r = 阅读全文
posted @ 2022-11-09 21:53 Whosedream-0019 阅读(30) 评论(0) 推荐(0)
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