随笔分类 -  递推

hdu 1249(递推)
摘要://递推,f(i) = f(i-1) + 6 * (i-1); f[1] = 2, i>=2;#include <cstdio>#include <iostream>using namespace std;int f[10001];int main() { int i; f[1] = 2; for (i=2; i<10001; ++i) f[i] = f[i-1] + 6 * (i - 1); int t; scanf ("%d", &t); while (t--) { int n; scanf ("%d", 阅读全文
posted @ 2012-04-05 18:30 Try86 阅读(257) 评论(0) 推荐(0)