hdu 1249(递推)

//递推,f(i) = f(i-1) + 6 * (i-1); f[1] = 2, i>=2;
#include <cstdio>
#include <iostream>

using namespace std;

int f[10001];

int main() {
int i;
f[1] = 2;
for (i=2; i<10001; ++i) f[i] = f[i-1] + 6 * (i - 1);
int t;
scanf ("%d", &t);
while (t--) {
int n;
scanf ("%d", &n);
printf ("%d\n", f[n]);
}
return 0;
}

 

posted on 2012-04-05 18:30  Try86  阅读(257)  评论(0)    收藏  举报