例题编写

例9.1程序

#include<stdio.h>
#include<stdlib.h>
int main()
{
    struct student
    {
    long int num;
    char name[20];
    char sex;
    char addr[20];
}
a={1,"sun",'m',"123 beijing road"};
printf("NO.:%ld\n name:%s\n sex:%c\n addr:%s\n",a.num,a.name,a.sex,a.addr);
return 0;
    
     
}

运行结果

NO.:1
 name:sun
 sex:m
 addr:123 beijing road

--------------------------------
Process exited after 0.006787 seconds with return value 0
请按任意键继续. . .

例9.2

#include<stdio.h>
#include<stdlib.h>
int main()
{
    struct student
    {
    long int num;
    char name[20];
    float score;
    
}student1,student2;
scanf("%d %s %f",&student1.num,student1.name,&student1.score);
scanf("%d %s %f",&student2.num,student2.name,&student2.score);
printf("The higher score is:\n");
if(student1.score>student2.score)
printf("%d %s %6.2f\n",student1.num,student1.name,student1.score);
else if(student1.score<student2.score)
printf("%d %s %6.2f\n",student2.num,student2.name,student2.score);
else{
printf("%d %s %6.2f\n",student1.num,student1.name,student1.score);
printf("%d %s %6.2f\n",student2.num,student2.name,student2.score);    
}
return 0;
}

运行结果:

189
290
The higher score is:
290.00

--------------------------------
Process exited after 78.92 seconds with return value 0
请按任意键继续. . .

例9.3:

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
    struct person
    {
    char name[20];
    int count;
}leader[3]={"li",0,"sun",0,"zhang",0};
int main()
{int i,j;
char leader_name[20];
for(i=0;i<=10;i++)
{
    scanf ("%s",leader_name);
    for(j=0;j<3;j++)
    if(strcmp(leader_name,leader[j].name)==0) leader[j].count++;
    
 } 
printf("\n Result:\n");
    for(i=0;i<3;i++)
    printf("%5s:%d\n",leader[i].name,leader[i].count);
    

    

return 0;
}

运行结果:

sun
li
liu
sun
li
li
liu
sun
li
lisun
li

 Result:
   li:5
  sun:3
zhang:0

--------------------------------
Process exited after 2.568 seconds with return value 0
请按任意键继续. . .

例9.4:

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
    struct student 
    { 
    int num;
    char name[20];
    float score;
};
int main()
{struct student stu[5]={{1,"zhang",69},{2,"sun",35},{3,"liu",56},{4,"dai",78},{5,"ham",67}};

 struct student temp;
 const int n=5;
 int i,j,k;
 printf("The order is:\n");
 for(i=0;i<n-1;i++)
 {k=i;
 for(j=i+1;j<n;j++)
 if(stu[j].score>stu[k].score)
 k=j;
 temp=stu[k];stu[k]=stu[i];stu[i]=temp;
 
  } 
  for(i=0;i<n-1;i++)
  printf("%6d %8s %6.2f\n",stu[i].num,stu[i].name,stu[i].score);
  printf("\n");
  return 0;
}

运行结果:

The order is:
     4      dai  78.00
     1    zhang  69.00
     5      ham  67.00
     3      liu  56.00


--------------------------------
Process exited after 0.01745 seconds with return value 0
请按任意键继续. . .

例9.5:

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int main()
{ 
    struct student 
    { 
    long num;
    char name[20];
    char sex;
    float score;
};
struct student stu_1;
struct student *p;
p=&stu_1;
stu_1.num=10101;
strcpy (stu_1.name,"liuxin");
stu_1.sex='m';
stu_1.score=89.5;
printf("NO.:%ld\n name:%s\n sex:%c\n score:%5.1f\n",stu_1.num,stu_1.name,stu_1.sex,stu_1.score);
printf("NO.:%ld\n name:%s\n sex:%c\n score:%5.1f\n",(*p).num,(*p).name,(*p).sex,(*p).score);

  return 0;
}

运行结果;

NO.:10101
 name:liuxin
 sex:m
 score: 89.5
NO.:10101
 name:liuxin
 sex:m
 score: 89.5

--------------------------------
Process exited after 0.06837 seconds with return value 0
请按任意键继续. . .

例9.6:

 

 

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
 
    struct student 
    { 
    long num;
    char name[20];
    char sex;
   int age;
};
struct student stu[3]={{1,"zhang",'m',17},{2,"sun",'m',17},{3,"liu",'m',18}};
int main()
{

struct student *p;
printf("NO. Name sex age\n");
for (p=stu;p<stu+3;p++)
printf("%5d %-20s %2c %4d\n",p->num,p->name,p->sex,p->age);

  return 0;
}
NO. Name sex age
    1 zhang                 m   17
    2 sun                   m   17
    3 liu                   m   18

--------------------------------
Process exited after 0.00648 seconds with return value 0
请按任意键继续. . .

例9.7;

#include<stdio.h>
#include<stdlib.h>

#define N 3

 
    struct student 
    { 
    int num;
    char name[20];
     float score[3];
     float aver;
};
int main()
{
void input(struct student stu[]    );
    struct student max(struct student stu[]);
    void print(struct student stu);
    struct student stu[N],*p=stu;
    input(p);
    print(max(p));
  return 0;
}

void input(    struct student stu[])
{int i;
printf("请输出各学生的信息:学号、姓名、三门课成绩:\n");
for(i=0;i<N;i++)
{
    scanf("%d %s%f%f%f",&stu[i].num,stu[i].name,&stu[i].score[0],&stu[i].score[1],&stu[i].score[2]);
    stu[i].aver=(stu[i].score[0]+stu[i].score[1]+stu[i].score[2])/3.0;
    
}
}
        struct student max(    struct student stu[] )
        {
            int i,m=0;
            for(i=0;i<N;i++)
            if(stu[i].aver>stu[m].aver) m=i;
            return stu[m];
        }
void print(struct student stud)
{printf("\n成绩最高的学生是:\n");
printf("学号:%d\n姓名:%d\n三门课成绩:%5.1f,%5.1f,%5.1f\n平均成绩:%6.2f\n",stud.num,stud.name,stud.score[0],stud.score[1],stud.score[2],stud.aver);

}

运行结果;

请输出各学生的信息:学号、姓名、三门课成绩:
10101 li 78 89 98
10103 wang 98.5 87 69
10106 sun 88 76.5 89

成绩最高的学生是:
学号:10101
姓名:10485108
三门课成绩: 78.0, 89.0, 98.0
平均成绩: 88.33

--------------------------------
Process exited after 99.13 seconds with return value 0
请按任意键继续. . .

 总结:经过这次例题抄写,我意识到指针这块的知识很明确。理解一个就可以举一反三。主要是结构体这块知识很杂。但是这次作业真的让我有很大提升。

posted on 2017-04-08 14:23  米粒呀  阅读(139)  评论(0编辑  收藏  举报

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