编程基本功——矩阵的乘法运算

一、分析

     解决矩阵相乘，比较简单的方式就是三重循环嵌套语句

二、源码

#include "stdio.h"

int main()
{
    int A[2][3] = {{1,2,3},{4,5,6}};
    int B[3][4] = {{1,0,2,3},{4,1,5,6},{6,8,9,0}};
    int C[2][4] = {{0,0,0,0},{0,0,0,0}};
    int i, j, k;
    for (i = 0; i < 2; ++i)
    {
        for (j = 0; j < 4; ++j)
        {
            for (k = 0; k <3; ++k)
            {
                C[i][j] += A[i][k] * B[k][j];
            }
        }
    }

    printf("The result is \n");
    for (i = 0; i < 2; ++i)
    {
        for (j = 0; j < 4; ++j)
        {
            printf("%d ", C[i][j]);
        }
        printf("\n");
    }

    return 0;
}