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创建二叉树求叶子节点个数

求二叉树叶子结点的个数,注意创建方法!

//求二叉树中叶子结点的个数

#include<iostream>
#define N 63

using namespace std;

char str[] = "ab#d##c#e##";  //先建立根节点,然后再左右结点建立
int i = -1;

typedef struct node
{
    struct node *leftChild;
    struct node *rightChild;
    char data;
}BiTreeNode, *BiTree;

//生成一个结点
BiTreeNode *createNode(int i)
{
    BiTreeNode * q = new BiTreeNode;
    q->leftChild = NULL;
    q->rightChild = NULL;
    q->data = i;
    return q;
}

BiTree createBiTree1()
{
    BiTreeNode *p[N] = { NULL };
    int i;
    for (i = 0; i < N; i++)
        p[i] = createNode(i + 1);

    // 把结点连接成树
    for (i = 0; i < N / 2; i++)
    {
        p[i]->leftChild = p[i * 2 + 1];
        p[i]->rightChild = p[i * 2 + 2];
    }

    return p[0];
}

void createBiTree2(BiTree &T)
{
    i++;
    char c;
    if (str[i] && '#' == (c = str[i]))
        T = NULL;
    else
    {
        T = new BiTreeNode;
        T->data = c;
        createBiTree2(T->leftChild);
        createBiTree2(T->rightChild);
    }
}

int getLeafNode(BiTree T)
{
    if (NULL == T)
        return 0;

    if (NULL == T->leftChild && NULL == T->rightChild)
        return 1;

    return getLeafNode(T->leftChild) + getLeafNode(T->rightChild);
}

int main()
{
    BiTree T1;
    T1 = createBiTree1();
    cout << getLeafNode(T1) << endl;

    BiTree T2;
    createBiTree2(T2);
    cout << getLeafNode(T2) << endl;

    return 0;
}

 

posted @ 2016-07-21 11:23  ranjiewen  阅读(...)  评论(...编辑  收藏