合集-AtCoder Solution

AtCoder Beginner Contest 365
摘要：A - Leap Year 思路 模拟即可; AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #define bs bitset using namespace 阅读全文
posted @ 2024-10-02 14:30 Oaths 阅读(9) 评论(0) 推荐(0)
AtCoder Beginner Contest 366
摘要：A - Election 2 思路 票数超过半数即为获胜，也可以将剩余票数都给少数者，若结果相同，则结束； AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #d 阅读全文
posted @ 2024-10-01 18:06 Oaths 阅读(30) 评论(0) 推荐(0)
AtCoder Beginner Contest 367
摘要：A - Shout Everyday 思路 分类区间讨论 AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #define bs bitset using nam 阅读全文
posted @ 2024-09-06 18:20 Oaths 阅读(7) 评论(0) 推荐(0)
AtCoder Beginner Contest 368
摘要：A - Cut 思路 按照题意输出即可，I/O问题 AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #define bs bitset using namesp 阅读全文
posted @ 2024-09-30 21:24 Oaths 阅读(8) 评论(0) 推荐(0)
AtCoder Beginner Contest 369
摘要：A - 369 思路 可能的位置只有左中右，如果\(A=B\)那么只有中间存在，如果\(A+B\)为奇数，那么只有中间不存在，反之均为3种； AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #defin 阅读全文
posted @ 2024-09-30 20:48 Oaths 阅读(11) 评论(0) 推荐(0)
AtCoder Beginner Contest 370
摘要：A - Raise Both Hands 思路 小模拟 AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #define bs bitset using name 阅读全文
posted @ 2024-09-08 16:02 Oaths 阅读(16) 评论(0) 推荐(0)
AtCoder Beginner Contest 371
摘要：A - Jiro 思路 创建变量a,b,c;根据输入进行增加，等于1的那个即为答案 AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #define bs bit 阅读全文
posted @ 2024-09-30 20:10 Oaths 阅读(10) 评论(0) 推荐(0)
AtCoder Beginner Contest 372
摘要：A - delete 思路 遇到'.'不输出就好 AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #define bs bitset using namespa 阅读全文
posted @ 2024-09-22 16:16 Oaths 阅读(55) 评论(0) 推荐(0)
AtCoder Beginner Contest 373
摘要：A - September 思路 判断字符串长度是否等于当前位次即可 AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #define bs bitset usi 阅读全文
posted @ 2024-09-29 18:42 Oaths 阅读(55) 评论(0) 推荐(0)
AtCoder Beginner Contest 374
摘要：A - Takahashi san 2 思路 取末三位的子串判断即可； AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #define bs bitset us 阅读全文
posted @ 2024-10-06 06:44 Oaths 阅读(79) 评论(0) 推荐(0)
AtCoder Beginner Contest 375
摘要：A - Seats 思路 枚举即可 AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #define bs bitset using namespace std; 阅读全文
posted @ 2024-10-13 13:23 Oaths 阅读(51) 评论(0) 推荐(0)
AtCoder Beginner Contest 376
摘要：A - Candy Button 思路 模拟 AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #define bs bitset using namespace 阅读全文
posted @ 2024-10-20 16:42 Oaths 阅读(53) 评论(0) 推荐(0)
AtCoder Beginner Contest 377
摘要：A - Rearranging ABC 思路 排序判断两串是否相等即可； AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #define bs bitset u 阅读全文
posted @ 2024-10-27 21:11 Oaths 阅读(71) 评论(0) 推荐(0)
AtCoder Beginner Contest 378
摘要：A - Pairing 思路 根据题意分类模拟判断即可 AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #define bs bitset using name 阅读全文
posted @ 2024-11-05 11:27 Oaths 阅读(54) 评论(0) 推荐(0)