10 2024 档案

AtCoder Beginner Contest 377
摘要：A - Rearranging ABC 思路 排序判断两串是否相等即可； AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #define bs bitset u 阅读全文
posted @ 2024-10-27 21:11 Oaths 阅读(62) 评论(0) 推荐(0)
AtCoder Beginner Contest 376
摘要：A - Candy Button 思路 模拟 AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #define bs bitset using namespace 阅读全文
posted @ 2024-10-20 16:42 Oaths 阅读(46) 评论(0) 推荐(0)
AtCoder Beginner Contest 375
摘要：A - Seats 思路 枚举即可 AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #define bs bitset using namespace std; 阅读全文
posted @ 2024-10-13 13:23 Oaths 阅读(50) 评论(0) 推荐(0)
AtCoder Beginner Contest 374
摘要：A - Takahashi san 2 思路 取末三位的子串判断即可； AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #define bs bitset us 阅读全文
posted @ 2024-10-06 06:44 Oaths 阅读(76) 评论(0) 推荐(0)
AtCoder Beginner Contest 365
摘要：A - Leap Year 思路 模拟即可; AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #define bs bitset using namespace 阅读全文
posted @ 2024-10-02 14:30 Oaths 阅读(8) 评论(0) 推荐(0)
AtCoder Beginner Contest 366
摘要：A - Election 2 思路 票数超过半数即为获胜，也可以将剩余票数都给少数者，若结果相同，则结束； AC代码 #include<bits/stdc++.h> #define endl '\n' #define int int long long #define pb push_back #d 阅读全文
posted @ 2024-10-01 18:06 Oaths 阅读(22) 评论(0) 推荐(0)