图片合集
- \(sin(2\theta)=2sin(\theta)cos(\theta)=\frac{2tan(\theta)}{1+tan^2(\theta)}\)
- \(cos(2\theta)=cos^2(\theta)-sin^2(\theta)=\frac{1-tan^2(\theta)}{1+tan^2(\theta)}\)
- \(tan(2\theta)=\frac{2tan(\theta)}{1-tan^2(\theta)}\)
- \(sin^2\theta= \frac {1-cos(2\theta)}2\)
- \(cos^2\theta=\frac {1+cos(2\theta)}2\)
- $ tan^2\theta=\frac{1-cos(2\theta)}{1+cos(2\theta)}$


















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