数学建模——灵敏度分析

数学规划与灵敏度分析

例题

解：

$$\mathit{m}\mathit{i}\mathit{n}\mathit{f}=\sum _{\mathit{j}=1}^4{\mathit{c}}_{\mathit{j}}{\mathit{x}}_{\mathit{j}}+\sum _{\mathit{j}=1}^3\left(\sum _{\mathit{i}=1}^{\mathit{j}}({\mathit{x}}_{\mathit{i}}-{\mathit{d}}_{\mathit{i}})\right){\mathit{e}}_{\mathit{j}+1}$$

lingo代码：

model:
sets:
     Z/1..4/:a,b,c,d;
endsets

data:
     a=6000,7000,12000,6000;
     b=70,71,80,76;
     d=2,2,2,2;
     m=10000;
enddata

min=@sum(z:c*b)+@sum(z(j)|j#le#3:@sum(Z(i)|i#le#j:(c-a)*d(j+1)));
@for(z(j)|j#le#3:@sum(z(i)|i#le#j:c)>@sum(z(i)|i#le#j:a));
@for(z(i):c<m);
@sum(Z:c)=@sum(z:a);

end

灵敏度分析
https://blog.csdn.net/weixin_51128278/article/details/117898155