摘要:
#include #include #include #define mod (int)(1e9+7) using namespace std; int main() { int t,n; scanf("%d",&t); while(t--) { scanf("%d",&n); long long ans1 = (1+n)*n/2... 阅读全文
摘要:
Description 985有n个正整数,他想快速知道下面函数的返回值 int a[N+1]; long long Solve() { int i, j; long long ans = 0; for(i = 1; i <= N; i++) { for(int j = i + 1; j <= N; 阅读全文
摘要:
Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Submit Status Submit Status Description Jesus, what a great movie! Thousands of p 阅读全文
摘要:
A -- Alarm Time Limit:1s Memory Limit:128MByte Submissions:179Solved:62 A -- Alarm Time Limit:1s Memory Limit:128MByte Submissions:179Solved:62 Time L 阅读全文