实验4

ex1:

方程的结果并不唯一,无法使用返回值

ex2:

 1 #include <stdio.h>
 2 long long fac(int n);
 3 
 4 int main() 
 5 {
 6     int i,n;
 7     
 8     printf("Enter n: ");
 9     scanf("%d", &n);
10     
11     for(i=1; i<=n; ++i) 
12         printf("%d! = %lld\n", i, fac(i)); 
13     
14     return 0;
15 }
16 long long fac(int n) 
17 {
18     static long long p = 1;
19     
20     p = p*n;
21     printf("p = %lld\n", p);
22     return p;
23 }

 

 1 #include<stdio.h>
 2 int func(int, int);
 3 
 4 int main() 
 5 {
 6     int k=4,m=1,p1,p2;
 7     
 8     p1 = func(k,m) ; 
 9     p2 = func(k,m) ;
10     printf("%d,%d\n",p1,p2) ;
11     
12     return 0;    
13 }
14 
15 int func(int a,int b) 
16 {   
17     static int m=0,i=2;
18     
19     i += m+1;
20     m = i+a+b;  
21     
22     return (m);
23 }

 

 

 static局部变量使得变量的值不会被重置

ex3:

 1 #include <stdio.h>
 2 
 3 #define N 1000
 4 int fun(int n,int m,int bb[N]) 
 5 {
 6     int i,j,k=0,flag;
 7     
 8     for(j=n;j<=m;j++) 
 9     {
10           flag=1;   
11         for(i=2;i<j;i++)
12             if(j%i==0) 
13             {  
14                flag=0;
15                break;
16             }
17         if(flag==1) 
18            bb[k++]=j;
19     }
20     return k;
21 }
22 
23 int main()
24 {
25     int n=0,m=0,i,k,bb[N];
26     
27     scanf("%d",&n);
28     scanf("%d",&m);
29     
30     for(i=0;i<m-n;i++)
31         bb[i]=0;
32         
33     k=fun(n,m,bb); 
34     
35     for(i=0;i<k;i++)
36         printf("%4d",bb[i]);
37         
38     return 0;
39 }

 

ex4:

 1 #include <stdio.h>
 2 long long fun(int n);
 3 
 4 int main() 
 5 {
 6     int n;
 7     long long f;
 8     
 9     while(scanf("%d", &n) != EOF) {
10         f = fun(n); 
11         printf("n = %d, f = %lld\n", n, f);
12     }
13     return 0;
14 }
15 long long fun(int n)
16 {
17     long long f;
18     if(n==0)
19     f=0;
20     else
21     f=2*fun(n-1)+1;
22     return f;
23 }

 

 ex5:

 1 #include <stdio.h>
 2 
 3 void draw(int n, char symbol);
 4 
 5 #include <stdio.h> 
 6 int main() {
 7     int n, symbol;
 8     
 9     while(scanf("%d %c", &n, &symbol) != EOF) {
10         draw(n, symbol);
11         
12         printf("\n");
13     }
14     
15     return 0;
16 } 
17 
18 void draw(int n,char symbol)
19 {
20     int a,b;
21     for(a=1;a<=n;a++)
22     {
23      for(b=1;b<=n-a;b++)
24      printf(" ");
25      for(b=1;b<=a*2-1;b++)
26      printf("%c",symbol);
27      printf("\n"); 
28     }
29 }

 

实验总结:函数的调用让思路变得更清晰

 

posted @ 2020-12-03 22:31  卷心菜投手  阅读(87)  评论(1编辑  收藏  举报