Java lambda表达式详解
Java lambda表达式是一种很有用很方便很常见的语法,先据一个例子:
public class Java8Tester {
public static void main(String args[]){
Java8Tester tester = new Java8Tester();
//with type declaration
MathOperation addition = (int a, int b) -> a + b;
//with out type declaration
MathOperation subtraction = (a, b) -> a - b;
//with return statement along with curly braces
MathOperation multiplication = (int a, int b) -> { return a * b; };
//without return statement and without curly braces
MathOperation division = (int a, int b) -> a / b;
System.out.println("10 + 5 = " + tester.operate(10, 5, addition));
System.out.println("10 - 5 = " + tester.operate(10, 5, subtraction));
System.out.println("10 x 5 = " + tester.operate(10, 5, multiplication));
System.out.println("10 / 5 = " + tester.operate(10, 5, division));
//without parenthesis
GreetingService greetService1 = message ->
System.out.println("Hello " + message);
//with parenthesis
GreetingService greetService2 = (message) ->
System.out.println("Hello " + message);
greetService1.sayMessage("Mahesh");
greetService2.sayMessage("Suresh");
}
interface MathOperation {
int operation(int a, int b);
}
interface GreetingService {
void sayMessage(String message);
}
private int operate(int a, int b, MathOperation mathOperation){
return mathOperation.operation(a, b);
}
}
可以看出Java lambda表达式的形式为 parameter -> expression。上面程序中如果不用lambda表达式,也可以实现,比如用类实现接口,然后生成对象,再调用之类的,或者好一点,也是用一个匿名类,但是这样会非常麻烦,远远没有lambda表达式简洁.
再看另一个例子。如果有一个Person列表,Person包含年龄,性别,名字等字段,现在要写一个根据条件过滤这个列表并打印出来等程序,用lambda表达式可以这么做:
import java.util.ArrayList;
import java.util.List;
import java.util.function.Consumer;
import java.util.function.Predicate;
class Person {
public enum Sex {
MALE, FEMALE
}
String name;
Sex gender;
int age;
String emailAddress;
public int getAge() {
return age;
}
public Sex getGender() {
return gender;
}
public void setGender(Sex gender) {
this.gender = gender;
}
public void printPerson() {
System.out.println( "The name is: "+ name + " at age: "+ age);
}
public Person(String name, Sex gender, int age, String emailAddress) {
this.name = name;
this.gender = gender;
this.age = age;
this.emailAddress = emailAddress;
}
}
public class Main {
public static void printPersonsWithPredicate(List<Person> roster, Predicate<Person> tester) {
for (Person p : roster) {
if (tester.test(p)) {
p.printPerson();
}
}
}
public static void processPersons(
List<Person> roster,
Predicate<Person> tester,
Consumer<Person> block) {
for (Person p : roster) {
if (tester.test(p)) {
block.accept(p);
}
}
}
public static void main(String[] args){
List<Person> pl = new ArrayList();
pl.add(new Person("Jet", Person.Sex.MALE, 21, "Jet@163.com"));
pl.add(new Person("Mike", Person.Sex.MALE, 18, "Mike@163.com"));
pl.add(new Person("Jim", Person.Sex.MALE, 28, "Jim@163.com"));
pl.add(new Person("Lucy", Person.Sex.FEMALE, 20, "Lucy@163.com"));
pl.add(new Person("Diana", Person.Sex.FEMALE, 28, "Diana@163.com"));
printPersonsWithPredicate(
pl,
p -> p.getGender() == Person.Sex.FEMALE
&& p.getAge() >= 18
&& p.getAge() <= 25
);
System.out.println("==========================");
processPersons(
pl,
p -> p.getGender() == Person.Sex.MALE
&& p.getAge() >= 18
&& p.getAge() <= 25,
p -> p.printPerson()
);
}
}
可以看到这里分别调用了Java的标准接口Predicate和Consumer,返回类型不同需要注意,然后我们用lambda表达式逻辑上实现它的test方法和accept,就可以正确使用了,是不是很方便?
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