jquery json

中英文 ajax action

ajax的post请求提交数据后台request对象获取不到数据

open("post","ajax");
ajax.setRequestHeader("Content-Type","application/x-www-form-urlencoded;charset=UTF-8");
ajax.send(uname + "&" + upwd);
 
原文链接:https://blog.csdn.net/hmh_java_life/article/details/104798982

posted on 2022-06-22 02:29  lydstory  阅读(22)  评论(0)    收藏  举报

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