随笔分类 - 算法-一些排序
摘要:重新学习算法,快排,算法导论中的 import "fmt" // Partition 分治这一部分 func Partition(A []int, l, r int) int { q := l - 1 for j := l; j < r; j++ { if A[j] <= A[r] { q++ A[
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摘要:1420 数袋鼠好有趣 题目来源: CodeForces 基准时间限制:1 秒 空间限制:131072 KB 分值: 40 难度:4级算法题 1420 数袋鼠好有趣 题目来源: CodeForces 基准时间限制:1 秒 空间限制:131072 KB 分值: 40 难度:4级算法题 1420 数袋鼠
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摘要:Genealogical tree Time Limit: 1000MS Memory Limit: 65536KTotal Submissions: 6032 Accepted: 3973 Special Judge Description The system of Martians' bloo
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摘要:FFF at Valentine Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 730 Accepted Submission(s): 359
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摘要:Hints of sd0061 Time Limit: 5000/2500 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 492 Accepted Submission(s): 106
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摘要:M - Ordering Tasks Time Limit:3000MS Memory Limit:0KB 64bit IO Format:%lld & %llu M - Ordering Tasks Time Limit:3000MS Memory Limit:0KB 64bit IO Forma
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摘要:H - Frosh Week Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u H - Frosh Week Time Limit:1000MS Memory Limit:32768KB 64bit IO For
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