排序查询
#进阶3:排序查询
/*
引入:
SELECT * FROM employees;
语法:
SELECT 查询列表
from 表
【where 筛选条件】
ORDER BY 排序列表【asc|desc】
特点:
1.asc代表的是升序,desc代表的是降序
如果不屑,默认是降序
2.ORDER BY 子句中可以支持单个字段、多个字段、表达式、函数、别名。
3.ORDER BY 子句一般是放在查询语句的最后面,limit子句除外
*/
#案例1:查询员工信息,要求工资从高到低排序
SELECT
*
FROM
employees
ORDER BY
salary DESC;
SELECT
*
FROM
employees
ORDER BY
salary;
#案例2:查询部门编号>=90的员工信息,按入职时间的先后排序
SELECT
*
FROM
employees
WHERE
department_id >= 90
ORDER BY
hiredate ASC;
#案例3:按年薪的高低显示员工的信息和年薪【按表达式排序】
SELECT
*, salary * 12 * (1 + IFNULL(commission_pct, 0)) AS 年薪
FROM
employees
ORDER BY
salary * 12 * (1 + IFNULL(commission_pct, 0)) DESC;
#案例4:按年薪的高低显示员工的信息和年薪【按表达式排序】
SELECT
*, salary * 12 * (1 + IFNULL(commission_pct, 0)) AS 年薪
FROM
employees
ORDER BY
年薪 DESC;
#案例5:按姓名的长度显示员工的姓名和工资【按函数排序】
SELECT
LENGTH(last_name) 字节长度,
last_name,
salary
FROM
employees
ORDER BY
LENGTH(last_name) DESC;
#案例6:查询员工信息,要求先按工资 升序,再按员工编号降序【按多个】
SELECT
*
FROM
employees
ORDER BY
employee_id DESC,
salary ASC;
#查询员工的姓名和部门号和年薪,按年薪降序排序,按姓名升序
SELECT
last_name,
department_id,
salary * 12 * (1 + IFNULL(commission_pct, 0)) AS 年薪
FROM
employees
ORDER BY
年薪 DESC,
last_name ASC;
#选择工资不在8000到17000的员工的姓名和工资,按工资降序
SELECT
last_name,
salary
FROM
employees
WHERE
salary NOT BETWEEN 8000
AND 17000
ORDER BY
salary DESC;
#查询邮箱中包含e的员工信息,并先按邮箱的字节数降序,再按部门号升序
SELECT
*, LENGTH(email) AS 邮箱长度
FROM
employees
WHERE
email LIKE '%e%'
ORDER BY
LENGTH(email) DESC,
department_id ASC;
本文来自博客园,作者:自律即自由-,转载请注明原文链接:https://www.cnblogs.com/deyo/p/13234138.html

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