实验三:类和对象Ⅱ

任务四:

//Vector_int.h
#ifndef LAB3_VECTOR_INT_H
#define LAB3_VECTOR_INT_H

#include "iostream"

using namespace std;

class Vector_int {
private:
    int n;
    int x;
    int *a;
public:
    explicit Vector_int(int num, int xx = 0) {
        n = num;
        x = xx;
        a = new int[n];
        for (int i = 0; i < n; i++)a[i] = x;
    }

    ~Vector_int() { delete[]a; }

    Vector_int(Vector_int &v) {
        n = v.n;
        a = new int[n];
        for (int i = 0; i < n; i++) {
            a[i] = v.a[i];
        }
        x = v.x;
    }

    int &at(int y) {
        return a[y];
    }

    void showa() {
        for (int i = 0; i < n; i++) {
            cout << a[i] << ' ';
        }
        cout << endl;
    }
};


#endif //LAB3_VECTOR_INT_H
//task4.cpp
#include <iostream>
#include "Vector_int.h"

using namespace std;

int main() {
    int n = 10;
    Vector_int x1(n);
    x1.showa();
    Vector_int x2(n, 6);
    x2.showa();
    Vector_int y(x2);
    y.at(6) = 99;
    y.showa();
}

 

实验五

//Matrix.h
#ifndef MATRIX_H
#define MATRIX_H

#include <iostream>
#include <cassert>

using namespace std;

class Matrix {
public:
    Matrix(int n);                     // 构造函数,构造一个n*n的矩阵
    Matrix(int n, int m);              // 构造函数,构造一个n*m的矩阵
    Matrix(const Matrix &X);           // 复制构造函数,使用已有的矩阵X构造
    ~Matrix();                         //析构函数
    void set(const double *pvalue);     // 用pvalue指向的连续内存块数据为矩阵赋值
    void set(int i, int j, int value); //设置矩阵第i行第j列元素值为value
    double &at(int i, int j);          //返回矩阵第i行第j列元素的引用
    double at(int i, int j) const;     // 返回矩阵第i行第j列元素的值
    int get_lines() const;             //返回矩阵行数
    int get_cols() const;              //返回矩列数
    void print() const;                // 按行打印输出矩阵
private:
    int lines; // 矩阵行数
    int cols;  // 矩阵列数
    double *p{}; // 指向存放矩阵数据的内存块的首地址
};


#endif
//Matrix.cpp
#include "Matrixx.h"

Matrix::Matrix(int n) {
    lines = n;
    cols = n;
    p = new double[n * n];
}

Matrix::Matrix(int n, int m) {
    lines = n;
    cols = m;
    p = new double[n * m];
}

Matrix::Matrix(const Matrix &X) {
    lines = X.lines;
    cols = X.cols;
    p = new double[lines * cols];
    for (int i = 0; i < lines * cols; i++) {
        p[i] = X.p[i];
    }
}

Matrix::~Matrix() {
    delete[]p;
}

void Matrix::set(const double *pvalue) {
    for (int i = 0; i < lines * cols; i++) {
        p[i] = pvalue[i];
    }
}

void Matrix::set(int i, int j, int value) {
    p[cols * i + j] = value;
}

double &Matrix::at(int i, int j) {
    return p[cols * i + j];
}

double Matrix::at(int i, int j) const {
    return p[cols * i + j];
}

int Matrix::get_lines() const {
    return lines;
}

int Matrix::get_cols() const {
    return cols;
}

void Matrix::print() const {
    int flag = 0;
    for (int i = 0; i < lines * cols; i++) {
        if (flag != 0 && flag % cols == 0)cout << endl;
        cout << p[i] << ' ';
        flag++;
    }
    cout << endl;
}
//task.cpp
#include <iostream>
#include "Matrixx.h"

int main() {
    using namespace std;

    double x[] = {1, 2, 3, 4, 5, 6};

    Matrix m1(3, 2);    // 创建一个3×2的矩阵
    m1.set(x);          // 用一维数组x的值按行为矩阵m1赋值
    m1.print();         // 打印矩阵m1的值
    cout << "the first line is: " << endl;
    cout << m1.at(0, 0) << " " << m1.at(0, 1) << endl;
    cout << endl;

    Matrix m2(2, 3);
    m2.set(x);
    m2.print();
    cout << "the first line is: " << endl;
    cout << m2.at(0, 0) << " " << m2.at(0, 1) << " " << m2.at(0, 2) << endl;
    cout << endl;

    Matrix m3(m2);
    m3.set(0, 0, 999);
    m3.print();
}

 

 

 

posted @ 2021-11-08 12:12  SFFFFFF  阅读(40)  评论(3)    收藏  举报
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