实验6

实验任务4

源代码

#include <stdio.h>
#define N 10

typedef struct {
    char isbn[20];      
    char name[80];      
    char author[80];    
    double sales_price;  
    int sales_count;     
} Book;

void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);

int main() {
    Book x[N] = {{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
                {"978-7-308-17047-5", "自由与爱之地: 入以色列记", "云也退", 49 , 30},
                {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
                {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90},
                {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
                {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
                {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
                {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
                {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
                {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}};

    printf("图书销量排名(按销售册数): \n");
    sort(x, N);
    output(x, N);
    printf("\n图书销售总额: %.2f\n", sales_amount(x, N));
    return 0;
}

void output(Book x[], int n) {
    printf("%-18s%-30s%-15s%8s%10s\n", "ISBN号", "书名", "作者", "售价", "销售册数");
    for (int i = 0; i < n; i++) {
        printf("%-18s%-30s%-15s%8.1f%10d\n", 
            x[i].isbn, x[i].name, x[i].author, 
            x[i].sales_price, x[i].sales_count);
    }
}

void sort(Book x[], int n) {
    for (int i = 0; i < n - 1; i++) {
        for (int j = 0; j < n - 1 - i; j++) {
            if (x[j].sales_count < x[j+1].sales_count) {
                Book temp = x[j];
                x[j] = x[j+1];
                x[j+1] = temp;
            }
        }
    }
}

double sales_amount(Book x[], int n) {
    double total = 0.0;
    for (int i = 0; i < n; i++) {
        total += x[i].sales_price * x[i].sales_count;
    }
    return total;
}

运行结果截图

 

 

实验任务5

源代码

 

#include <stdio.h>

typedef struct {
    int year;
    int month;
    int day;
} Date;

void input(Date *pd);              
int day_of_year(Date d);            
int compare_dates(Date d1, Date d2);

void test1() {
    Date d;
    int i;
    printf("输入日期:(以形如2025-12-19这样的形式输入)\n");
    for(i = 0; i < 3; ++i) {
        input(&d);
        printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d));
    }
}

void test2() {
    Date Alice_birth, Bob_birth;
    int i;
    int ans;
    printf("输入Alice和Bob出生日期:(以形如2025-12-19这样的形式输入)\n");
    for(i = 0; i < 3; ++i) {
        input(&Alice_birth);
        input(&Bob_birth);
        ans = compare_dates(Alice_birth, Bob_birth);
        if(ans == 0)
            printf("Alice和Bob一样大\n\n");
        else if(ans == -1)
            printf("Alice比Bob小\n\n");
        else
            printf("Alice比Bob大\n\n");
    }
}

void input(Date *pd) {
    scanf("%d-%d-%d", &pd->year, &pd->month, &pd->day);
}

int day_of_year(Date d) {
    int days_of_month[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    if ((d.year % 4 == 0 && d.year % 100 != 0) || (d.year % 400 == 0)) {
        days_of_month[2] = 29;
    }
    int total = 0;
    for (int i = 1; i < d.month; i++) {
        total += days_of_month[i];
    }
    total += d.day;
    return total;
}

int compare_dates(Date d1, Date d2) {
    if (d1.year != d2.year) {
        return d1.year < d2.year ? -1 : 1;
    }
    if (d1.month != d2.month) {
        return d1.month < d2.month ? -1 : 1;
    }
    if (d1.day != d2.day) {
        return d1.day < d2.day ? -1 : 1;
    }
    return 0;
}

int main() {
    printf("测试1: 输入日期，打印输出这是一年中第多少天\n");
    test1();
    printf("\n测试2: 两个人年龄大小关系\n");
    test2();
    return 0;
}

 

运行结果截图

 

 

实验任务6

源代码

 

#include <stdio.h>
#include <string.h>

enum Role {admin, student, teacher};
typedef struct {
    char username[20];  
    char password[20];  
    enum Role type;     
} Account;

void output(Account x[], int n); 

int main() {
    Account x[] = {{"A1001", "123456", student},
                    {"A1002", "123abcdef", student},
                    {"A1009", "xyz12121", student},
                    {"x1009", "9213071x", admin},
                    {"c11553", "129dfg32k", teacher},
                    {"x3005", "921kfmg917", student}};
    int n;
    n = sizeof(x)/sizeof(Account);
    output(x, n);
    return 0;
}

void output(Account x[], int n) {
    char *role_names[] = {"admin", "student", "teacher"};
    
    for (int i = 0; i < n; i++) {
        printf("%-10s", x[i].username);
        
        int pwd_len = strlen(x[i].password);
        for (int j = 0; j < pwd_len; j++) {
            putchar('*');
        }
        printf("%*s%s\n", 16 - pwd_len, "", role_names[x[i].type]);
    }
}

 

运行结果截图

 

 

实验任务7

源代码

 

#include <stdio.h>
#include <string.h>

typedef struct {
    char name[20];     
    char phone[12];    
    int vip;           
} Contact;

void set_vip_contact(Contact x[], int n, char name[]);  
void output(Contact x[], int n);   
void display(Contact x[], int n);  

#define N 10
int main() {
    Contact list[N] = {{"刘一", "15510846604", 0},
                        {"陈二", "18038747351", 0},
                        {"张三", "18853253914", 0},
                        {"李四", "13230584477", 0},
                        {"王五", "15547571923", 0},
                        {"赵六", "18856659351", 0},
                        {"周六", "17705843215", 0},
                        {"孙八", "15552933732", 0},
                        {"吴九", "18077702405", 0},
                        {"郑十", "18820725036", 0}};
    int vip_cnt, i;
    char name[20];
    printf("显示原始通讯录信息: \n");
    output(list, N);
    printf("\n输入要设置的紧急联系人个数: ");
    scanf("%d", &vip_cnt);
    printf("输入%d个紧急联系人姓名:\n", vip_cnt);
    for(i = 0; i < vip_cnt; ++i) {
        scanf("%s", name);
        set_vip_contact(list, N, name);
    }
    printf("\n显示通讯录列表:(按姓名字典序排列,紧急联系人最先显示)\n");
    display(list, N);
    return 0;
}

void set_vip_contact(Contact x[], int n, char name[]) {
    for (int i = 0; i < n; i++) {
        if (strcmp(x[i].name, name) == 0) {
            x[i].vip = 1;
            return;
        }
    }
}

void output(Contact x[], int n) {
    int i;
    for(i = 0; i < n; i++) {
        printf("%-10s%-15s", x[i].name, x[i].phone);
        if(x[i].vip)
            printf("%5s", "*");
        printf("\n");
    }
}

void swap(Contact *a, Contact *b) {
    Contact temp = *a;
    *a = *b;
    *b = temp;
}

void display(Contact x[], int n) {
    for (int i = 0; i < n - 1; i++) {
        for (int j = 0; j < n - 1 - i; j++) {
            if (x[j].vip < x[j+1].vip) {
                swap(&x[j], &x[j+1]);
            }
        }
    }
    int vip_end = 0;
    while (vip_end < n && x[vip_end].vip == 1) {
        vip_end++;
    }
    for (int i = 0; i < vip_end - 1; i++) {
        for (int j = 0; j < vip_end - 1 - i; j++) {
            if (strcmp(x[j].name, x[j+1].name) > 0) {
                swap(&x[j], &x[j+1]);
            }
        }
    }
    for (int i = vip_end; i < n - 1; i++) {
        for (int j = vip_end; j < n - 1 - (i - vip_end); j++) {
            if (strcmp(x[j].name, x[j+1].name) > 0) {
                swap(&x[j], &x[j+1]);
            }
        }
    }
    output(x, n);
}

 

运行结果截图