大三今日总结 .

本题要求实现一个函数,将两个链表表示的递增整数序列合并为一个非递减的整数序列。
List Merge(List L1, List L2) {
List L = (List)malloc(sizeof(struct Node));
List p = L;
List p1 = L1->Next;
List p2 = L2->Next;
while (p1!= NULL && p2!= NULL) {
if (p1->Data < p2->Data) {
p->Next = p1;
p1 = p1->Next;
} else {
p->Next = p2;
p2 = p2->Next;
}
p = p->Next;
}
if (p1!= NULL) {
p->Next = p1;
}
if (p2!= NULL) {
p->Next = p2;
}
L1->Next = NULL;
L2->Next = NULL;
return L;
}

include <stdio.h>

include <stdlib.h>

typedef int ElementType;
typedef struct Node *PtrToNode;
struct Node {
ElementType Data;
PtrToNode Next;
};
typedef PtrToNode List;

List Read(); /* 细节在此不表 /
void Print( List L ); /
细节在此不表;空链表将输出NULL */

List Merge( List L1, List L2 );

int main()
{
List L1, L2, L;
L1 = Read();
L2 = Read();
L = Merge(L1, L2);
Print(L);
Print(L1);
Print(L2);
return 0;
}

posted @ 2026-01-13 23:51  C(5,3)  阅读(12)  评论(0)    收藏  举报