摘要: $$ \begin{aligned} &已知数列\{a_n\}满足a_1=2t-3(t\in \mathbb{R}且t\neq \pm 1),\\ &a_{n+1}=\cfrac{(2t^{n+1}-3)a_n+2(t-1)t^n-1}{a_n+2t^n-1}(n\in \mathbb{N}^*)\\ &(1)求数列\{a_n\}的通项公式。\\ &(2)若t>0,比较a_{n}与a_{n+1}的大小。\\ \end{aligned} $$ 阅读全文
posted @ 2021-10-03 10:59 毕天驰 阅读(78) 评论(0) 推荐(0)