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C# WinForm 用MenuStrip动态生成菜单并动态加载事件

2011-09-27 11:13  ※森林小居※  阅读(15855)  评论(9编辑  收藏  举报

最近在做WINFORM开发,一直都在为主界面的点击事件及动态加载菜单苦脑。现在已解决这个问题了,可以实现数据库或都XML等配置完成动态生成菜单及事件加载。代码如下:

private void Form1_Load(object sender, EventArgs e)
        {
            //添加菜单一 
            ToolStripMenuItem subItem;
            subItem = AddContextMenu("入库", menuStrip1.Items, null);
            //添加子菜单 
            AddContextMenu("添加入库", subItem.DropDownItems, new EventHandler(MenuClicked));
            AddContextMenu("入库管理", subItem.DropDownItems, new EventHandler(MenuClicked));

            //添加菜单二 
            subItem = AddContextMenu("出库", menuStrip1.Items, null);
            //添加子菜单 
            AddContextMenu("添加出库", subItem.DropDownItems, new EventHandler(MenuClicked));
            AddContextMenu("出库管理", subItem.DropDownItems, new EventHandler(MenuClicked));
        }

 

        /// <summary>
        /// 添加子菜单
        /// </summary>
        /// <param name="text">要显示的文字,如果为 - 则显示为分割线</param>
        /// <param name="cms">要添加到的子菜单集合</param>
        /// <param name="callback">点击时触发的事件</param>
        /// <returns>生成的子菜单,如果为分隔条则返回null</returns>

        ToolStripMenuItem AddContextMenu(string text, ToolStripItemCollection cms, EventHandler callback)
        {
            if (text == "-")
            {
                ToolStripSeparator tsp = new ToolStripSeparator();
                cms.Add(tsp);
                return null;
            }
            else if (!string.IsNullOrEmpty(text))
            {
                ToolStripMenuItem tsmi = new ToolStripMenuItem(text);
                tsmi.Tag = text + "TAG";
                if (callback != null) tsmi.Click += callback;
                cms.Add(tsmi);

                return tsmi;
            }

            return null;
        }

        void MenuClicked(object sender, EventArgs e)
        {
     //以下主要是动态生成事件并打开窗体

    //((sender as ToolStripMenuItem).Tag)强制转换

            ObjectHandle t = Activator.CreateInstance("WinForms", "WinForms.Form2");
            Form f = (Form)t.Unwrap();
            f.ShowDialog();

        }