ASP .NET 返回Json操作结果

返回string

var A="...";
var B="...";
$.ajax({
        type: "POST",
        url: "/Controller/Action",
        data: { "A": A,"B": B},
        success: function (result) {
                layer.alert(result, '操作结果');
        }
});
public ActionResult Action(string A,string B)
{
    ABManager manager =new ABManager();
    string result =manager.DoSomething(A, B);
    return Json(result, JsonRequestBehavior.AllowGet);
}

返回匿名对象

<div><button onclick="GetResult()">点击</button></div>
<script>
    function GetResult() {
        var A = "A";
        var B = "B";
        $.ajax({
            type: "POST",
            url: "/AboutC/ReturnObjectFromCAjax",
            data: { "A": A, "B": B },
            success: function (result) {
                if (result.Success == true) {
                    layer.alert('操作成功,结果为' + result.A + "," + result.B);
                }
                else {
                    layer.msg('操作失败,请稍后重试...');
                }
            }
        });
    }
</script>
public ActionResult ReturnObjectFromCAjax(string A,string B)
{
    return Json(new
    {
        A = A + "_ok",
        B = B + "_ok",
        Success=true
    });
}
posted @ 2017-11-21 16:16  Lulus  阅读(669)  评论(0编辑  收藏  举报