【BZOJ2324】[ZJOI2011]营救皮卡丘 给定起点最小权K链可相交覆盖

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef int JQK;int n, m, k, dis[205][205];
int main() {
        int u, v, c;
        scanf("%d %d %d", &n, &m, &k);
        memset(dis, 63, sizeof(dis));
        for (int i = 1; i <= m; i++) {
                scanf("%d %d %d", &u, &v, &c);
                dis[u][v] = dis[v][u] = min(dis[u][v], c);
        }
        for (int k = 0; k <= n; k++) {
                for (int i = 0; i <= n; i++) {
                        for (int j = 0; j <= n; j++) {
                                if (k <= i || k <= j)
                                        dis[i][j] = min(dis[i][j], dis[i][k] + dis[k][j]);
                        }
                }
        }
        int s, t;
        s = 2 * (n + 1) + 2, t = s + 1;
        MCMF::MAXP = t + 1;
        MCMF::init(s, t);
        MCMF::addedge(s, 0, k, 0);
        for (int i = 1; i <= n; i++) {
                MCMF::addedge(s, i, 1, 0);
                MCMF::addedge(i + n, t, 1, 0);
        }
        for (int i = 0; i <= n; i++) {
                for (int j = i + 1; j <= n; j++) {
                        MCMF::addedge(i, j + n, 1, dis[i][j]);
                }
        }
        cout << MCMF::mcmf();
        return 0;
}

 

posted @ 2019-10-29 00:31  Aragaki  阅读(127)  评论(0)    收藏  举报