实验六
实验四
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1 #include <stdio.h> 2 #define N 10 3 4 typedef struct { 5 char isbn[20]; 6 char name[80]; 7 char author[80]; 8 double sales_price; 9 int sales_count; 10 } Book; 11 12 void output(Book x[], int n); 13 void sort(Book x[], int n); 14 double sales_amount(Book x[], int n); 15 16 int main() { 17 Book x[N] = { 18 {"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51}, 19 {"978-7-308-17047-5", "自由与爱之地:入以色列记", "云也退", 49, 30}, 20 {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27}, 21 {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90}, 22 {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49}, 23 {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42}, 24 {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44}, 25 {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42}, 26 {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55}, 27 {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59} 28 }; 29 printf("图书销量排名(按销售册数): \n"); 30 sort(x, N); 31 output(x, N); 32 printf("\n图书销售总额: %.2f\n", sales_amount(x, N)); 33 return 0; 34 } 35 36 void output(Book x[], int n) { 37 printf("%-20s %-30s %-20s %-6s %s\n", "ISBN号", "书名", "作者", "售价", "销售册数"); 38 int i; 39 for (i = 0; i < n; i++) { 40 if (x[i].sales_price == (int)x[i].sales_price) 41 printf("%-20s %-30s %-20s %6d %6d\n", 42 x[i].isbn, x[i].name, x[i].author, (int)x[i].sales_price, x[i].sales_count); 43 else 44 printf("%-20s %-30s %-20s %6.1f %6d\n", 45 x[i].isbn, x[i].name, x[i].author, x[i].sales_price, x[i].sales_count); 46 } 47 } 48 49 void sort(Book x[], int n) { 50 int i; 51 for (i = 0; i < n - 1; i++) { 52 int max_idx = i; 53 int j; 54 for (j = i + 1; j < n; j++) { 55 if (x[j].sales_count > x[max_idx].sales_count) 56 max_idx = j; 57 } 58 if (max_idx != i) { 59 Book temp = x[i]; 60 x[i] = x[max_idx]; 61 x[max_idx] = temp; 62 } 63 } 64 } 65 66 double sales_amount(Book x[], int n) { 67 double total = 0.0; 68 int i; 69 for (i = 0; i < n; i++) { 70 total += x[i].sales_price * x[i].sales_count; 71 } 72 return total; 73 }

实验五
1 #include <stdio.h> 2 3 typedef struct { 4 int year; 5 int month; 6 int day; 7 } Date; 8 9 void input(Date *pd); 10 int day_of_year(Date d); 11 int compare_dates(Date d1, Date d2); 12 13 void test1() { 14 Date d; 15 int i; 16 printf("输入日期:(以形如2025-12-19这样的形式输入)\n"); 17 for(i = 0; i < 3; ++i) { 18 input(&d); 19 printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d)); 20 } 21 } 22 23 void test2() { 24 Date Alice_birth, Bob_birth; 25 int i; 26 int ans; 27 printf("输入Alice和Bob出生日期:(以形如2025-12-19这样的形式输入)\n"); 28 for(i = 0; i < 3; ++i) { 29 input(&Alice_birth); 30 input(&Bob_birth); 31 ans = compare_dates(Alice_birth, Bob_birth); 32 if(ans == 0) 33 printf("Alice和Bob一样大\n\n"); 34 else if(ans == -1) 35 printf("Alice比Bob大\n\n"); 36 else 37 printf("Alice比Bob小\n\n"); 38 } 39 } 40 41 int main() { 42 printf("测试1: 输入日期, 打印输出这是一年中第多少天\n"); 43 test1(); 44 printf("\n测试2: 两个人年龄大小关系\n"); 45 test2(); 46 return 0; 47 } 48 49 void input(Date *pd) { 50 scanf("%d-%d-%d", &pd->year, &pd->month, &pd->day); 51 } 52 53 int day_of_year(Date d) { 54 int days_in_month[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; 55 if ((d.year % 4 == 0 && d.year % 100 != 0) || (d.year % 400 == 0)) 56 days_in_month[1] = 29; 57 int i; 58 int total = 0; 59 for (i = 0; i < d.month - 1; i++) 60 total += days_in_month[i]; 61 total += d.day; 62 return total; 63 } 64 65 int compare_dates(Date d1, Date d2) { 66 if (d1.year < d2.year) return -1; 67 if (d1.year > d2.year) return 1; 68 if (d1.month < d2.month) return -1; 69 if (d1.month > d2.month) return 1; 70 if (d1.day < d2.day) return -1; 71 if (d1.day > d2.day) return 1; 72 return 0; 73 }

实验六
1 #include <stdio.h> 2 #include <string.h> 3 4 enum Role { admin, student, teacher }; 5 6 typedef struct { 7 char username[20]; 8 char password[20]; 9 enum Role type; 10 } Account; 11 12 void output(Account x[], int n); 13 14 int main() { 15 Account x[] = { 16 {"A1001", "123456", student}, 17 {"A1002", "123abcdef", student}, 18 {"A1009", "xyz12121", student}, 19 {"X1009", "9213071x", admin}, 20 {"C11553", "129dfg32k", teacher}, 21 {"X3005", "921kfmg917", student} 22 }; 23 int n = sizeof(x) / sizeof(Account); 24 output(x, n); 25 return 0; 26 } 27 28 void output(Account x[], int n) { 29 int i; 30 int a=13; 31 for (i = 0; i < n; i++) { 32 printf("%-10s ", x[i].username); 33 int len = strlen(x[i].password); 34 int j; 35 for (j = 0; j < len; j++) { 36 printf("*"); 37 } 38 for (j=0;j<a-len;j++) 39 printf(" "); 40 switch (x[i].type) { 41 case admin: printf("admin\n"); break; 42 case student: printf("student\n"); break; 43 case teacher: printf("teacher\n"); break; 44 } 45 } 46 }

实验七
1 #include <stdio.h> 2 #include <string.h> 3 4 typedef struct { 5 char name[20]; 6 char phone[12]; 7 int vip; 8 } Contact; 9 10 void set_vip_contact(Contact x[], int n, char name[]); 11 void output(Contact x[], int n); 12 void display(Contact x[], int n); 13 14 #define N 10 15 16 int main() { 17 Contact list[N] = { 18 {"刘一", "15510846604", 0}, 19 {"陈二", "18038747351", 0}, 20 {"张三", "18853253914", 0}, 21 {"李四", "13230584477", 0}, 22 {"王五", "15547571923", 0}, 23 {"赵六", "18856659351", 0}, 24 {"周七", "17705843215", 0}, 25 {"孙八", "15552933732", 0}, 26 {"吴九", "18077702405", 0}, 27 {"郑十", "18820725036", 0} 28 }; 29 int vip_cnt, i; 30 char name[20]; 31 printf("显示原始通讯录信息:\n"); 32 output(list, N); 33 printf("\n输入要设置的紧急联系人个数: "); 34 scanf("%d", &vip_cnt); 35 printf("输入%d个紧急联系人姓名:\n", vip_cnt); 36 for(i = 0; i < vip_cnt; ++i) { 37 scanf("%s", name); 38 set_vip_contact(list, N, name); 39 } 40 printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n"); 41 display(list, N); 42 return 0; 43 } 44 45 void set_vip_contact(Contact x[], int n, char name[]) { 46 int i; 47 for (i = 0; i < n; ++i) { 48 if (strcmp(x[i].name, name) == 0) { 49 x[i].vip = 1; 50 break; 51 } 52 } 53 } 54 55 void output(Contact x[], int n) { 56 int i; 57 for (i = 0; i < n; ++i) { 58 printf("%-10s%-15s", x[i].name, x[i].phone); 59 if (x[i].vip) 60 printf("%5s", "*"); 61 printf("\n"); 62 } 63 } 64 65 void display(Contact x[], int n) { 66 Contact temp[N]; 67 int i; 68 for (i = 0; i < n; ++i) 69 temp[i] = x[i]; 70 for (i = 0; i < n - 1; ++i) { 71 int j; 72 for (j = 0; j < n - i - 1; ++j) { 73 if (temp[j].vip < temp[j+1].vip) { 74 Contact t = temp[j]; 75 temp[j] = temp[j+1]; 76 temp[j+1] = t; 77 } else if (temp[j].vip == temp[j+1].vip) { 78 if (strcmp(temp[j].name, temp[j+1].name) > 0) { 79 Contact t = temp[j]; 80 temp[j] = temp[j+1]; 81 temp[j+1] = t; 82 } 83 } 84 } 85 } 86 for (i = 0; i < n; ++i) { 87 printf("%-10s%-15s", temp[i].name, temp[i].phone); 88 if (temp[i].vip) 89 printf("%5s", "*"); 90 printf("\n"); 91 } 92 }


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