随笔分类 -  模拟,贪心

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摘要:Roll-call in Woop Woop HighTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 188Accepted Submission(... 阅读全文
posted @ 2015-08-14 09:17 柳下_MBX 阅读(210) 评论(0) 推荐(0)
摘要:Avoiding a disasterTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 211Accepted Submission(s): 101P... 阅读全文
posted @ 2015-08-14 09:02 柳下_MBX 阅读(321) 评论(0) 推荐(0)
摘要:Eqs Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 13967 Accepted: 6858 Description Consider equations having the following form: a1x13+ a 阅读全文
posted @ 2015-08-03 23:51 柳下_MBX 阅读(436) 评论(0) 推荐(0)
摘要:B - Attack at the Orbit Time Limit:1000MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64u Submit Status Practice URAL 1942 B - Attack at the Orbit 阅读全文
posted @ 2015-07-30 08:36 柳下_MBX 阅读(342) 评论(0) 推荐(0)
摘要:D - Record of the Attack at the Orbit Time Limit:1000MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64uSubmit Status Practice URAL 1944DescriptionT... 阅读全文
posted @ 2015-07-29 19:26 柳下_MBX 阅读(392) 评论(0) 推荐(0)
摘要:欢迎参加——BestCoder周年纪念赛(高质量题目+多重奖励) Ugly WindowsTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1481A... 阅读全文
posted @ 2015-07-27 19:59 柳下_MBX 阅读(199) 评论(0) 推荐(0)
摘要:欢迎参加——BestCoder周年纪念赛(高质量题目+多重奖励) Priest John's Busiest Day Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submi 阅读全文
posted @ 2015-07-27 18:56 柳下_MBX 阅读(241) 评论(0) 推荐(0)
摘要:F - Finding Seats Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1937 F - Finding Seats Submit Status 阅读全文
posted @ 2015-07-27 09:04 柳下_MBX 阅读(619) 评论(0) 推荐(0)
摘要:#include#include#include#includeusing namespace std;char str1[100005],str2[100005];bool vis[100005];int main(){ while(scanf("%s",str1)!=EOF){ ge... 阅读全文
posted @ 2015-07-23 18:26 柳下_MBX 阅读(260) 评论(0) 推荐(0)
摘要:Spring-outing DecisionTime Limit: 3000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 676Accepted Submission(s): 2... 阅读全文
posted @ 2015-07-23 08:37 柳下_MBX 阅读(205) 评论(0) 推荐(0)
摘要:Emag eht htiw Em PlehTime Limit:1000MSMemory Limit:65536KTotal Submissions:2944Accepted:1949DescriptionThis problem is a reverse case of theproblem 29... 阅读全文
posted @ 2015-07-07 23:52 柳下_MBX 阅读(190) 评论(0) 推荐(0)
摘要:Robot MotionTime Limit:1000MSMemory Limit:10000KTotal Submissions:11270Accepted:5487DescriptionA robot has been programmed to follow the instructions ... 阅读全文
posted @ 2015-07-07 23:02 柳下_MBX 阅读(146) 评论(0) 推荐(0)
摘要:Crashing RobotsTime Limit: 1000MSMemory Limit: 65536KTotal Submissions: 8388Accepted: 3631DescriptionIn a modernized warehouse, robots are used to fet... 阅读全文
posted @ 2015-07-07 21:47 柳下_MBX 阅读(126) 评论(0) 推荐(0)
摘要:TautologyTime Limit: 1000MSMemory Limit: 65536KTotal Submissions: 10453Accepted: 3967DescriptionWFF 'N PROOF is a logic game played with dice. Each di... 阅读全文
posted @ 2015-07-07 13:27 柳下_MBX 阅读(217) 评论(0) 推荐(0)
摘要:Help Me with the GameTime Limit:1000MSMemory Limit:65536KTotal Submissions:3713Accepted:2376DescriptionYour task is to read a picture of a chessboard ... 阅读全文
posted @ 2015-07-06 22:25 柳下_MBX 阅读(188) 评论(0) 推荐(0)
摘要:Y2K Accounting Bug Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 11275 Accepted: 5675 Description Accounting for Computer Machinists (ACM 阅读全文
posted @ 2015-07-03 00:00 柳下_MBX 阅读(251) 评论(0) 推荐(0)
摘要:Radar Installation Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 60381 Accepted: 13610 Description Assume the coasting is an infinite str 阅读全文
posted @ 2015-07-02 21:18 柳下_MBX 阅读(275) 评论(0) 推荐(0)
摘要:The Pilots Brothers' refrigerator Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 20398 Accepted: 7857 Special Judge Description The game “ 阅读全文
posted @ 2015-07-02 13:54 柳下_MBX 阅读(131) 评论(0) 推荐(0)
摘要:Flip Game Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 33670 Accepted: 14713 Description Flip game is played on a rectangular 4x4 field 阅读全文
posted @ 2015-06-30 20:58 柳下_MBX 阅读(276) 评论(0) 推荐(0)
摘要:#include<stdio.h>#include<string.h>#include<iostream>#include<algorithm>using namespace std;int num[6],sum[6];int mi(int num[],int a[],int count1){ in 阅读全文
posted @ 2015-04-21 03:37 柳下_MBX 阅读(255) 评论(0) 推荐(0)

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