代码随想录算法训练营第30天
今日刷题3道:39. 组合总和,40.组合总和II,131.分割回文串
class Solution {
private:
vector<vector<int>> result;
vector<int> path;
void backtracking(vector<int>& candidates, int sum, int target, int index){
if(sum > target) return;
if(sum == target){
result.push_back(path);
return;
}
for(int i=index;i<candidates.size();i++){
sum+=candidates[i];
path.push_back(candidates[i]);
backtracking(candidates,sum,target,i);
sum-=candidates[i];
path.pop_back();
}
}
public:
vector<vector<int>> combinationSum(vector<int>& candidates, int target) {
backtracking(candidates,0,target,0);
return result;
}
};
class Solution {
private:
vector<vector<int>> result;
vector<int> path;
void backtracking(vector<int>& candidates, int sum, int target, int index, vector<bool>& used){
if(sum > target) return;
if(sum == target){
result.push_back(path);
return;
}
for(int i=index;i<candidates.size();i++){
if(i>0 && candidates[i]==candidates[i-1] && used[i-1] == false){
continue;
}
sum+=candidates[i];
path.push_back(candidates[i]);
used[i]=true;
backtracking(candidates,sum,target,i+1,used);
used[i]=false;
sum-=candidates[i];
path.pop_back();
}
}
public:
vector<vector<int>> combinationSum2(vector<int>& candidates, int target) {
vector<bool> used(candidates.size(),false);
sort(candidates.begin(),candidates.end());
backtracking(candidates,0,target,0, used);
return result;
}
};
● 131.分割回文串
https://programmercarl.com/0131.%E5%88%86%E5%89%B2%E5%9B%9E%E6%96%87%E4%B8%B2.html
视频讲解:https://www.bilibili.com/video/BV1c54y1e7k6
class Solution {
private:
vector<vector<string>> result;
vector<string> path;
void backtracking(const string& s, int startIndex){
if(startIndex >= s.size()){
result.push_back(path);
return;
}
for(int i=startIndex;i<s.size();i++){
if(isPalindrome(s,startIndex,i)){
string str = s.substr(startIndex,i-startIndex+1);
path.push_back(str);
}else{
continue;
}
backtracking(s,i+1);
path.pop_back();
}
}
bool isPalindrome(const string& s, int start, int end){
for(int i=start,j=end;i<j;i++,j--){
if(s[i]!=s[j]){
return false;
}
}
return true;
}
public:
vector<vector<string>> partition(string s) {
backtracking(s,0);
return result;
}
};