实验三

task 1

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#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <windows.h>
#define N 80

void print_text(int line, int col, char text[]);   
void print_spaces(int n); 
void print_blank_lines(int n);  

int main() {
	int line, col, i;
	char text[N] = "hi, April~";
	
	srand(time(0)); 
	
	for(i = 1; i <= 10; ++i) {
		line = rand() % 25;
		col =  rand() % 80;
		print_text(line, col, text);
		Sleep(1000); 
	}
	
	return 0; 
}


void print_spaces(int n) {
	int i;
	
	for(i = 1; i <= n; ++i)
		printf(" ");
}


void print_blank_lines(int n) {
	int i;
	
	for(i = 1; i <= n; ++i)
		printf("\n");
 } 


void print_text(int line, int col, char text[]) {
	print_blank_lines(line-1);  	
	print_spaces(col-1);			
	printf("%s", text);         
}

task 2

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#include <stdio.h>
#include<stdlib.h>
long long fac(int n); // 函数声明

int main() {
    int i, n;

    printf("Enter n: ");
    scanf("%d", &n);

    for (i = 1; i <= n; ++i)
	printf("%d! = %lld\n", i, fac(i));
	system("pause:");
    return 0;
}

// 函数定义
long long fac(int n) {
    static long long p = 1;

    p = p * n;

    return p;
}

点击查看代码

#include <stdio.h>
#include<stdlib.h>
long long fac(int n); // 函数声明

int main() {
    int i, n;

    printf("Enter n: ");
    scanf("%d", &n);

    for (i = 1; i <= n; ++i)
	printf("%d! = %lld\n", i, fac(i));
	system("pause:");
    return 0;
}

// 函数定义
long long fac(int n) {
    static long long p = 1;
	printf("p = %lld\n", p); 
    p = p * n;

    return p;
}

点击查看代码

#include<stdlib.h>
#include <stdio.h>
int func(int, int);		

int main() {
    int k = 4, m = 1, p1, p2;

    p1 = func(k, m);	
    p2 = func(k, m);	
    printf("%d, %d\n", p1, p2);
	system("pause:");
    return 0;
}


int func(int a, int b) {
    static int m = 0, i = 2;

    i += m + 1;
    m = i + a + b;

    return m;
}

task 3

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#include <stdio.h>
#include<stdlib.h>
long long func(int n); // 函数声明

int main() {
    int n;
    long long f;

    while (scanf("%d", &n) != EOF) {
        f = func(n); // 函数调用
        printf("n = %d, f = %lld\n", n, f);
    }
	system("pause:");
    return 0;
}
long long func(int n)
{
	if(n>=1)
		return 2*func(n-1)+1;
	else if(n==0)
		return 0;

}

task 4

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#include <stdio.h>
#include<stdlib.h>
int func(int n, int m);

int main() {
    int n, m;

    while(scanf("%d%d", &n, &m) != EOF)
        printf("n = %d, m = %d, ans = %d\n", n, m, func(n, m));
    system("pause:");
    return 0;
}
int func(int n, int m){
	int i, a, b ,c;
	if (n < m)
		return 0;
	else if (n== m==0)
		return 1;
	else 
		{for (i = n; i >= n - m + 1; i--)
			a *= i;
		for (b = 1; b <= m; b++)
			c *= b;
		return a / c;}

}


点击查看代码

#include <stdio.h>
#include<stdlib.h>
int func(int n, int m);

int main() {
    int n, m;

    while(scanf("%d%d", &n, &m) != EOF)
        printf("n = %d, m = %d, ans = %d\n", n, m, func(n, m));
    system("pause:");
    return 0;
}
int func(int n, int m){
	if (m == n == 0)
		return 1;
	
	else if (m > n) 
		return 0;
	
	else 
	return func(n - 1, m) + func(n - 1, m - 1);
	
}

task 5

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#include <stdio.h>
#include<stdlib.h>
void hanio(int n,char from,char temp,char to); 
void moveplate(int n,char from,char to);
int sum(int n);
int main() 
{
	int k;
	char A,B,C;
	int n;
	while(scanf("%d",&n)!=EOF)
	{
   hanio(n,'A','B','C');
   k=sum(n);
   printf("一共移动了%d次\n",k);
	system("pause");
	}
    return 0;
}
void moveplate(int n,char from,char to)
{
	
	printf("%d : %c --> %c\n",n,from,to);

}
void hanio(int n,char from,char temp,char to)
{
	if(n==1){
		moveplate(n,from,to);}
	if(n>1)
	{
	hanio(n-1,from,to,temp);
	moveplate(n,from,to);
	hanio(n-1,temp,from,to);
	}
}
int sum(int n)
{
	if(n==1){
		return 1;}
	if(n>1){
		return 2*sum(n-1)+1;}

}


task 6

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#include <stdio.h>
#include <math.h>
#include<stdlib.h>
long func(long s);   

int main() {

    long s, t;

    printf("Enter a number: ");
    while (scanf("%ld", &s) != EOF) {
        t = func(s);
        printf("new number is: %ld\n\n", t);
        printf("Enter a number: ");
    }
	system("pause:");
    return 0;
}
long func(long s){
    long a, b, c;
    a = 0;
    c = 1;

    while (s != 0) {
        b = s % 10;
        if (b % 2) {
            a += c * b;
            c *= 10;
        }

        s /= 10;
    }
        return a;

}