实验5

任务1_1：

代码：

#include<stdio.h>
#define N 4

int main()
{
    int x[N] = {1,9,8,4};
    int i;
    int *p;
    
    for(i = 0;i < N;++i)
    printf("%d",x[i]);
    printf("\n");
    
    for(p = x;p < x + N;++p)
    printf("%d",*p);
    printf("\n");
    
    p = x;
    for(i = 0;i < N;++i)
    printf("%d",*(p + i));
    printf("\n");
    
    p = x;
    for(i = 0;i < N;++i)
    printf("%d",p[i]);
    printf("\n");
    return 0; 
}

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任务1_2:

代码：

#include <stdio.h>

int main()
{
    int x[2][4] = {{1,9,8,4},{2,0,4,9}};
    int i,j;
    int *p;
    int(*q)[4];
    
    for(i = 0;i < 2;++i)
    {for(j = 0;j < 4;++j)
    printf("%d",x[i][j]);
    printf("\n");
    }
    
    for(p = &x[0][0],i = 0;p < &x[0][0] + 8;++p,++i)
    {
        printf("%d",*p);
        if((i + 1)%4==0)
        printf("\n");
    }
        for(q = x;q < x + 2;++q)
        {for(j = 0;j < 4;++j)
        printf("%d",*(*q+j));
        printf("\n");
        }
        return 0;
    
}

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任务2_1：

代码：

#include <stdio.h>
#include <string.h>
#define N 80

int main()
{
    char s1[] = "Learning makes me happy";
    char s2[] = "Learning makes me sleepy";
    char tmp[N];
    
    printf("sizeof(s1) vs. strlen(s1):\n");
    printf("sizeof(s1) = %d\n",sizeof(s1));
    printf("strlen(s1) = %d\n",strlen(s1));
    
    printf("\nbefore swap:\n");
    printf("s1:%s\n",s1);
    printf("s2:%s\n",s2);
    
    printf("\nswapping...\n");
    strcpy(tmp,s1);
    strcpy(s1,s2);
    strcpy(s2,tmp);
    
    printf("\nafter swap:\n");
    printf("s1:%s\n",s1);
    printf("s2:%s\n",s2);
    return 0;
}

截图：

结论：

1.24，计算占用的字节数，统计除空格外有效字符的个数

2.不能，定义的是字符型的数组，必须要带方括号

3.s1与s2互换

任务2_2：

代码：

#include <stdio.h>
#include <string.h>
#define N 80

int main()
{
    char *s1 = "Learning makes me happy";
    char *s2 = "Learning makes me sleepy";
    char *tmp;
    
    printf("sizeof(s1) vs. strlen(s1):\n");
    printf("sizeof(s1) = %d\n",sizeof(s1));
    printf("strlen(s1) = %d\n",strlen(s1));
    
    printf("\nbefore swap:\n");
    printf("s1:%s\n",s1);
    printf("s2:%s\n",s2);
    
    printf("\nswapping...\n");
    tmp = s1;
    s1 = s2;
    s2 = tmp;
    
    printf("\nafter swap:\n");
    printf("s1:%s\n",s1);
    printf("s2:%s\n",s2);
    
    return 0;
}

截图：

结论：

1.字符串的起始地址，第一个单词的长度，字符串的字符数

2.可以，这个s1是指针变量，上一个s1是地址常量

3.交换的是地址，两个字符串常量没有交换

任务3：

代码：

#include <stdio.h>

void str_spy(char *target,const char *source);
void str_cat(char *str1,char *str2);

int main()
{
    char s1[80],s2[20] = "1984";
    
    str_cpy(s1,s2);
    puts(s1);
    
    str_cat(s1,"Animal Farm");
    puts(s1);
    
    return 0;
}
void str_cpy(char *target,const char *source)
{
    while(*target++ = *source++);
}
void str_cat(char *str1,char *str2)
{
    while(*str1)
    str1++;
    
    while(*str1++ = *str2++);
}

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任务4：

代码：

#include <stdio.h>
#define N 80
int func(char *);

int main()
{
    char str[80];
    
    while (gets(str)!=NULL)
    {
        if(func(str))
        printf("yes\n");
        else
        printf("no\n");
    }
    return 0;
}
int func(char *str)
{
    char *begin,*end;
    
    begin = end = str;
    
    while(*end)
    end++;
    
    end--;
    
    while(begin < end)
    {
        if(*begin!=*end)
        return 0;
        else
        {
            begin++;
            end--;
        }
    }
    return 1;
}

截图：

任务5：

代码：

#include <stdio.h>
#define N 80

void func(char *);

int main()
{
    char s[N];
    
    while (scanf("%s",s)!=EOF){
        func(s);
        puts(s);
    }
    return 0;
}
void func(char *str)
{
    int i;
    char *p1,*p2,*p;
    
    p1 = str;
    while(*p1 == '*')
    p1++;
    p2 = str;
    while(*p2)
    p2++;
    p2--;
    
    while(*p2 == '*')
    p2--;
    
    p = str;
    i = 0;
    while(p < p1)
    {
        str[i] = *p;
        p++;
        i++;
        
    }
    while(p <= p2)
    {
        if(*p!='*')
        {
            str[i] = *p;
            i++;
        }
        p++;
    }
    while(*p!='\0')
    {
        str[i] = *p;
        p++;
        i++;
    }
    str[i] = '\0';
}

截图：

任务6_1：

代码：

#include <stdio.h>
#include <string.h>
void sort(char *name[],int n);

int main()
{
    char *course[4] = {"C Program",
    "C++ Object Oriented Profram",
    "Operating System",
    "Data Structure and Algorithms"};
    int i;
    
    sort(course,4);
    
    for(i = 0;i < 4;i++)
    printf("%s\n",course[i]);
    
    return 0;
}
void sort(char *name[],int n)
{
    int i,j;
    char *tmp;
    
    for(i = 0;i<n-1;++i)
    for(j = 0;j<n-1-i;++j)
    if(strcmp(name[j],name[j+1])>0)
    {
        tmp = name[j];
        name[j] = name[j+1];
        name[j+1] = tmp;
    }
}

截图：

任务6_2:

代码：

#include <stdio.h>
#include <string.h>
void sort(char *name[],int n);

int main()
{
    char *course[4] = {"C Program",
    "C++ Object Oriented Profram",
    "Operating System",
    "Data Structure and Algorithms"};
    int i;
    
    sort(course,4);
    for(i = 0;i<4;i++)
    printf("%s\n",course[i]);
    
    return 0;
}
void sort(char *name[],int n)
{
    int i,j,k;
    char *tmp;
    
    for(i = 0;i<n-1;i++)
    {
        k = i;
        for(j = 1+1;j<n;j++)
        if(strcmp(name[j],name[k])<0)
        k = j;
        
        if(k!=i)
        {
            tmp = name[i];
            name[i] = name[k];
            name[k] = tmp;
        }
    }
}

截图：

结论：交换的是指针变量的值

任务7：

代码：

#include <stdio.h>
#include <string.h>
#define N 5
int check_id(char *str);

int main()
{
    char *pid[N] = {"31010120000721656X",
      "330106199609203301",
      "53010220051126571",
     "510104199211197977",
     "53010220051126133Y"};
int i;
for(i = 0;i<N;++i)
if(check_id(pid[i]))
printf("%s\tTrue\n",pid[i]);
else
printf("%s\tFalse\n",pid[i]);

return 0;
}
int check_id(char *str)
 {
     char *p;
     p = str;
     while((*p>='0'&&*p<='9')||*p=='X')
         p++;
     if(*p=='\0'&&strlen(str)==18)
         return 1;
     else
         return 0;
 }

截图：

任务8：

代码：

#include <stdio.h>
#define N 80
void encoder(char *s);
void decoder(char *s);

int main()
{
    char words[N];
    
    printf("输入英文文本：");
    gets(words);
    
    printf("编码后的英文文本：");
    encoder(words);
    printf("%s\n",words);
    
    printf("对编码后的英文文本解码：");
    decoder(words);
    printf("%s\n",words);
    
    return 0;
     
}

void encoder(char *s)
{
    while(*s!='\0')
    if(*s>=65 && *s<=90 ||*s>=97 && *s<=122)
    {*s=*s+1;
    *s++;
    continue;
    }
    else if(*s=='z'||*s=='Z')
    {
    *s=*s-25;
    *s++;
    continue;}

else
*s++;}
void decoder(char *s)
{
    while(*s!='\0')
    if(*s>=65 && *s<=90 || *s>=97 && *s<=122)
    {
    *s=*s-1;
    *s++;
    continue;
}
else if(*s=='a' || *s=='A')
{
    *s = *s+25;
    *s++;
    continue;
    
}
else 
s++;
}

截图：

posted @ 2023-05-10 20:58 0波波茶0 阅读(14) 评论(0) 收藏举报

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实验5

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