实验2
task1
#include <stdio.h> #include <stdlib.h> #include <time.h> #define N 5 #define R1 586 #define R2 701 int main() { int number; int i; srand(time(0)); for(i = 0; i < N; ++i) { number = rand() % (R2 - R1 + 1) + R1; printf("20228330%04d\n", number); } return 0; }

回答问题:1、在R1和R2之间随机取一个数
2、在202283300586和202283300701之间随机抽取5个学号
task2
#include <stdio.h> int main() { double x, y; char c1, c2 ,c3; int a1, a2, a3; scanf("%d%d%d", &a1, &a2, &a3);//error printf("a1 = %d, a2 = %d, a3 = %d\n", a1, a2, a3); scanf("%c%c%c", &c1, &c2, &c3); printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3); scanf("%lf,%lf", &x, &y);//error printf("x = %lf, y = %lf\n", x, y); return 0; }

tsak3-2
#include <stdio.h> #include <math.h> int main() { double x, ans; while(scanf("%lf", &x) != EOF){ ans = pow(x, 365); printf("%.2f的365次方:%.2f\n", x, ans); printf("\n"); } return 0; }



task3-3
#include <stdio.h> int main() { double c, f; while(scanf("%lf", &c) != EOF) { f = 9 * c / 5 + 32; printf("摄氏度c = %.2lf时,华氏度f = %.2lf\n", c, f); printf("\n"); } return 0; }

task4
#include <stdio.h> int main() { char ans; while(scanf("%c", &ans)!= EOF) { switch(ans){ case 'r' :printf("stop!\n");break; case 'g' :printf("go go go\n");break; case 'y' :printf("wait a minute\n");break; default:printf("something must be wrong...\n"); } getchar(); } return 0; }

task5
#include <stdio.h> #include <stdlib.h> #include <time.h> int main() { int n, x, i; srand(time(0)); n = rand() % 30 + 1; printf("猜猜2023年4月哪一天会是你的lucky day\n开始喽,你有三次机会,猜吧(1~30):"); scanf("%d", &x); for(i = 1;i <= 3; i++){ if(x > n) printf("你猜的日期晚了,你的lucky day已经过啦\n"); else if(x < n) printf("你猜的日期早了,你的lucky day还没到呢\n"); if(i != 3){ printf("再猜(1~30):"); scanf("%d", &x);} else break; } if(x == n){ printf("哇,猜中啦~"); i = 4 ;} if(i == 3) printf("\n次数用完啦。偷偷告诉你:4月,你的lucky day是%d号", n); return 0; }


task6
#include <stdio.h> int main() { int i, j; for(i = 1; i <= 9; i++) { for(j = 1; j <= i; j++) printf("%d * %d = %d\t", j, i, i*j); printf("\n"); } return 0; }

task7
#include <stdio.h> int main() { int n, i, j, m; printf("input n:"); scanf("%d", &n); for(j = 1;j <= n;j++){ for(i = 1;i <= j;i++) {printf("\t");} for(i = 1;i <= (n - j) * 2 + 1;i++) { printf(" O \t");} printf("\n"); for(i = 1;i <= j;i++) {printf("\t");} for(i = 1;i <= (n - j) * 2 + 1;i++) { printf("<H>\t");} printf("\n"); for(i = 1;i <= j;i++) {printf("\t");} for(i = 1;i <= (n - j) * 2 + 1;i++) { printf("I I\t");} printf("\n\n"); }


回答问题:1、(n - i) * 2 + 1个小人
2、 i - 1个空格

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