Sorting It All Out
An ascending sorted sequence of distinct values is one in which some form of a less-than operator is used to order the elements from smallest to largest. For example, the sorted sequence A, B, C, D implies that A < B, B < C and C < D. in this problem, we will give you a set of relations of the form A < B and ask you to determine whether a sorted order has been specified or not.
输入
Input consists of multiple problem instances. Each instance starts with a line containing two positive integers n and m. the first value indicated the number of objects to sort, where 2 <= n <= 26. The objects to be sorted will be the first n characters of the uppercase alphabet. The second value m indicates the number of relations of the form A < B which will be given in this problem instance. Next will be m lines, each containing one such relation consisting of three characters: an uppercase letter, the character "<" and a second uppercase letter. No letter will be outside the range of the first n letters of the alphabet. Values of n = m = 0 indicate end of input.
输出
For each problem instance, output consists of one line. This line should be one of the following three:
Sorted sequence determined after xxx relations: yyy...y.
Sorted sequence cannot be determined.
Inconsistency found after xxx relations.
where xxx is the number of relations processed at the time either a sorted sequence is determined or an inconsistency is found, whichever comes first, and yyy...y is the sorted, ascending sequence.
Sorted sequence determined after xxx relations: yyy...y.
Sorted sequence cannot be determined.
Inconsistency found after xxx relations.
where xxx is the number of relations processed at the time either a sorted sequence is determined or an inconsistency is found, whichever comes first, and yyy...y is the sorted, ascending sequence.
样例输入
4 6
A<B
A<C
B<C
C<D
B<D
A<B
3 2
A<B
B<A
26 1
A<Z
0 0
样例输出
Sorted sequence determined after 4 relations: ABCD.
Inconsistency found after 2 relations.
Sorted sequence cannot be determined.
#include <bits/stdc++.h>
#define maxn 10005
using namespace std;
typedef long long ll;
struct Edge
{
int v,next;
};
struct M
{
Edge edge[maxn];
int head[maxn];
int cnt;
void init()
{
memset(head,-1, sizeof(head));
cnt=0;
}
void addedge(int u,int v)
{
edge[cnt].v=v;
edge[cnt].next=head[u];
head[u]=cnt++;
}
}Mp;
int ind[30],n,in[30];
int Low_ans[maxn];
int Upper_ans[maxn];
set<char> se;
bool Low_Topsort()
{
int tot=-1;
priority_queue<int,vector<int>,greater<int> > q;
for(int i=0;i<26;i++)
{
if(ind[i]==0&&se.count(i+'A')) q.push(i);
}
while(!q.empty())
{
int u=q.top();
q.pop();
Low_ans[++tot]=u;
for(int i=Mp.head[u];i!=-1;i=Mp.edge[i].next)
{
int v=Mp.edge[i].v;
ind[v]--;
if(ind[v]==0) q.push(v);
}
}
if(tot==se.size()-1) return true;
else return false;
}
void Upper_Topsort()
{
int tot=-1;
priority_queue<int> q;
for(int i=0;i<26;i++)
{
if(ind[i]==0&&se.count(i+'A')) q.push(i);
}
while(!q.empty())
{
int u=q.top();
q.pop();
Upper_ans[++tot]=u;
for(int i=Mp.head[u];i!=-1;i=Mp.edge[i].next)
{
int v=Mp.edge[i].v;
ind[v]--;
if(ind[v]==0) q.push(v);
}
}
}
int main()
{
int m,i;
//freopen("in.txt","r",stdin);
while(~scanf("%d%d",&n,&m))
{ if(n==0&&m==0) break;
se.clear();
Mp.init();
int f=0;
int cnt=0;
int ans[maxn]={0};
memset(in,0, sizeof(in));
for(int i=1;i<=m;i++)
{
string s;
memset(Low_ans,0, sizeof(Low_ans));
memset(Upper_ans,0, sizeof(Upper_ans));
cin>>s;
se.insert(s[0]);
se.insert(s[2]);
Mp.addedge(s[0]-'A',s[2]-'A');
in[s[2]-'A']++;
for(int i=0;i<26;i++)
{
ind[i]=in[i];
}
if(!Low_Topsort()&&!f)
{
f=1;
cnt=i;
}
else
{
for(int i=0;i<26;i++)
{
ind[i]=in[i];
}
Upper_Topsort();
//printf("\n");
bool flag=true;
for(int i=0;i<se.size();i++)
{
if(Low_ans[i]!=Upper_ans[i])
{
flag=false;
break;
}
}
if(flag&&!f&&se.size()==n)
{
f=2;
cnt=i;
for(int i=0;i<se.size();i++)
{
ans[i]=Low_ans[i];
}
}
}
}
if(!f)
{
cout<<"Sorted sequence cannot be determined."<<endl;
}
else if(f==1)
{
printf("Inconsistency found after %d relations.\n",cnt);
}
else if(f==2)
{
printf("Sorted sequence determined after %d relations: ",cnt);
for(int i=0;i<se.size();i++)
{
printf("%c",ans[i]+'A');
}
printf(".");
printf("\n");
}
}
return 0;
}

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