协程-小脚本

# __author: "ZXYang"
# date: 2020/5/20


def f():
print('11')
count = yield 111111
print(count)
print('33')
yield 333333


r1 = f() # 迭代

# next(r1)
# next(r1)

# rr1 = next(r1)
# rr2 = next(r1)
# print(rr1)
# print(rr2)

r1.send(None) # 先发个None,等同于 ==》第一个rr1 = next(r1)
rr3 = r1.send(10)
# print(rr3)
posted @ 2020-12-22 21:13  zxy_ang  阅读(93)  评论(0)    收藏  举报