字典排序 

dicts = {'zhang':22,'wang':44,'li':31,'zhao':27}
s = sorted(dicts.items(),key=lambda x:x[0])
print(s)
ss = sorted(dicts.items(), key=lambda x:x[1])
print(ss)
posted @ 2018-09-27 18:38  exchange<>  阅读(82)  评论(0)  编辑  收藏  举报