java求两个数组中相同元素出现的次数

法一

public class Methodfifth {

public void mixed(int array1[], int n1, int array2[], int n2)
{
int i = 0, j = 0,number=0;
while (i < n1&&j < n2)
{
if (array1[i] == array2[j])
{
number++;


i++;
j++;


}
else if (array1[i]>array2[j])
{
j++;
}
else if (array1[i] < array2[j])
{
i++;
}
}
System.out.println("出现相同数的次数为"+number);
}
public static void main(String[] args) {
int a[] = { 0, 1, 2, 3, 4 };
int b[] = { 1, 3, 5, 7, 9 };
Methodfifth m=new Methodfifth();
m. mixed(a, 5, b, 5);

}

 

法二

public class MethodSixth {
public void mixed(int array1[], int n1, int array2[], int n2)
{
int i = 0, j = 0,number=0;
for(;i<array1.length;i++){
for(;j<array1.length;j++){
{
if (array1[i] == array2[j])
{
number++;





}

}
}

System.out.println("出现相同数的ge数为"+number);
}
}
public static void main(String[] args) {
int a[] = { 0, 1, 2, 3, 4 };
int b[] = { 1, 3, 5, 7, 9 };
Methodfifth m=new Methodfifth();
m. mixed(a, a.length, b, b.length );