随笔分类 - 字符串 kmp
摘要:A Secret Problem Description Today is the birthday of SF,so VS gives two strings S1,S2 to SF as a present,which have a big secret.SF is interested in
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摘要:Classic Quotation Problem Description When online chatting, we can save what somebody said to form his ''Classic Quotation''. Little Q does this, too.
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摘要:题目链接:传送门 题解: 利用KMP的fail失配数组,快速找到当前后缀与前缀的公共前缀点
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摘要:题目链接:传送门 题解: 枚举每一行,每一行当中连续的y个我们hash 出来 那么一行就是 m - y + 1个hash值,形成的一个新 矩阵 大小是 n*(m - y + 1), 我们要找到x*y这个矩阵的 话 是不是就是 在每一列跑kmp就行了?
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摘要:题目链接:传送门 题意: 给你一个串S 你可以在结尾补充任意数量字母,问最少数量使得新串是回文串 题解: KMP 将S串倒置跑KMP
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摘要:Sequence I Problem Description Mr. Frog has two sequences a1,a2,⋯,an and b1,b2,⋯,bm and a number p. He wants to know the number of positions q such th
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摘要:Hamed has recently found a string t and suddenly became quite fond of it. He spent several days trying to find all occurrences of t in other strings h
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摘要:D. MUH and Cube WallsPolar bears Menshykov and Uslada from the zoo of St. Petersburg and elephant Horace from the zoo of Kiev got hold of lots of wood...
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摘要:题意: 给你一个串T,找出串T的子串,该串既是T的前缀也是T的后缀。从小到大输出所有符合要求的串的长度。分析: 首先要知道KMP的next[i]数组求得的数值就是串T中的[1,i-1]的后缀与串T中的[0,i-2]前缀的最大匹配长度。 所以next[m](m为串长且串从0到m-1下标)的...
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摘要:Milking GridTime Limit:3000MSMemory Limit:65536KTotal Submissions:7153Accepted:3047DescriptionEvery morning when they are ...
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摘要:题意:统计其中一个子串的出现次数题解:即KMP算法中j==m的次数//作者:1085422276#include #include #include #include #include #include #include #include #include #include #include //#...
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摘要:题目链接:http://acm.hust.edu.cn/vjudge/problem/viewProblem.action?id=36131题意:给出一个长度为n的字符串,要求找到一些i,满足说从1~i为多个个的重复子串构成,并输出子串的个数。题解:对kmp中预处理的数组的理解 //作者:10854...
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摘要:Simpsons’ Hidden TalentsTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4683Accepted Submission(s)...
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