[leetcode]Remove Duplicates from Sorted Array II @ Python

原题地址:https://oj.leetcode.com/problems/remove-duplicates-from-sorted-array-ii/

题意:

Follow up for "Remove Duplicates":
What if duplicates are allowed at most twice?

For example,
Given sorted array A = [1,1,1,2,2,3],

Your function should return length = 5, and A is now [1,1,2,2,3].

解题思路:一种巧妙的解法。使用两个指针prev和curr,判断A[curr]是否和A[prev]、A[prev-1]相等,如果相等curr指针继续向后遍历,直到不相等时,将curr指针指向的值赋值给A[prev+1],这样多余的数就都被交换到后面去了。最后prev+1值就是数组的长度。

代码:

class Solution:
    # @param A a list of integers
    # @return an integer
    # @it's a good solution!
    def removeDuplicates(self, A):
        if len(A) <= 2: return len(A)
        prev = 1; curr = 2
        while curr < len(A):
            if A[curr] == A[prev] and  A[curr] == A[prev - 1]:
                curr += 1
            else:
                prev += 1
                A[prev] = A[curr]
                curr += 1
        return prev + 1

 

posted @ 2014-06-12 10:49  南郭子綦  阅读(2740)  评论(0编辑  收藏  举报