Java 结构体排序

题目大意:给出10万条直线,求是否存在交点于x1,x2之间
题目链接:http://codeforces.com/contest/593/problem/B
import java.io.*;
import java.math.*;
import java.util.*;

public class Main {
    static class node {
        long y1, y2;

        node(long a, long b) {
            y1 = a;
            y2 = b;
        }
    }

    static class cmp implements Comparator<node> {
        // 从小到大
        public int compare(node A, node B) {
            if (A.y1 == B.y1) {
                if (A.y2 > B.y2)
                    return 1;
                else
                    return -1;
            }
            if (A.y1 > B.y1)
                return 1;
            else
                return -1;
        }
    }

    public static void main(String[] argc) {
        Scanner cin = new Scanner(System.in);
        int i;
        node[] p = new node[100005];
        while (cin.hasNext()) {
            long n = cin.nextLong();
            long x1 = cin.nextLong();
            long x2 = cin.nextLong();
            for (i = 0; i < n; i++) {
                long a = cin.nextLong();
                long b = cin.nextLong();
                p[i] = new node(a * x1 + b, a * x2 + b);
            }
            Arrays.sort(p, 0, (int) n, new cmp());

            for (i = 1; i < n; i++) {
                if (p[i].y1 != p[i - 1].y1)
                    if (p[i].y2 < p[i - 1].y2)
                        break;
            }
            if (i == n)
                System.out.println("NO");
            else
                System.out.println("YES");
        }
    }
}
 

 

        Collections.sort(apiMainModels, new Comparator<ApiMainModel>() {
            @Override
            public int compare(ApiMainModel o1, ApiMainModel o2) {
                return o1.getApi_right().compareTo(o2.getApi_right());
            }
        });

 

posted on 2015-11-27 19:39  13rj1115  阅读(302)  评论(0)    收藏  举报

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