a letter and a number

描述

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

输入

On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).

输出

for each case, you should the result of y+f(x) on a line

样例输入

6
R 1
P 2
G 3
r 1
p 2
g 3

样例输出

19
18
10
-17
-14
-4

#include <stdio.h>
#include <ctype.h>

int main(){
    int T;
    char c;
    int n;
    int result;
    
    scanf("%d",&T);
    getchar();
    
    while(T--){
        scanf("%c %d",&c,&n);
        getchar();
        
        if(islower(c)){
            result=-(c-'a'+1)+n;
        }
        
        else
            result=c-'A'+1+n;
            
        printf("%d\n",result);
    }
    return 0;
}