JS中Float类型加减乘除 修复 

 1  //浮点数加法运算
 2 function FloatAdd(arg1,arg2){
 3     var r1,r2,m;
 4     try{r1=arg1.toString().split(".")[1].length}catch(e){r1=0}
 5     try{r2=arg2.toString().split(".")[1].length}catch(e){r2=0}
 6     m=Math.pow(10,Math.max(r1,r2));
 7     return (arg1*m+arg2*m)/m;
 8 }
 9 
10 //浮点数减法运算
11 function FloatSub(arg1,arg2){
12     var r1,r2,m,n;
13     try{r1=arg1.toString().split(".")[1].length}catch(e){r1=0}
14     try{r2=arg2.toString().split(".")[1].length}catch(e){r2=0}
15     m=Math.pow(10,Math.max(r1,r2));
16     //动态控制精度长度
17     n=(r1=r2)?r1:r2;
18     return ((arg1*m-arg2*m)/m).toFixed(n);
19 }
20 
21 //浮点数乘法运算
22 function FloatMul(arg1,arg2)
23 {
24     var m=0,s1=arg1.toString(),s2=arg2.toString();
25     try{m+=s1.split(".")[1].length}catch(e){}
26     try{m+=s2.split(".")[1].length}catch(e){}
27     return Number(s1.replace(".",""))*Number(s2.replace(".",""))/Math.pow(10,m);
28 }
29 
30 
31  //浮点数除法运算
32 function FloatDiv(arg1,arg2){
33     var t1=0,t2=0,r1,r2;
34     try{t1=arg1.toString().split(".")[1].length}catch(e){}
35     try{t2=arg2.toString().split(".")[1].length}catch(e){}
36     with(Math){
37         r1=Number(arg1.toString().replace(".",""));
38         r2=Number(arg2.toString().replace(".",""));
39         return (r1/r2)*pow(10,t2-t1);
40     }
41 }
42

 

posted @ 2017-07-16 18:42  躺着就赢了  阅读(1460)  评论(0)    收藏  举报