python数字运算

1.加减乘除(+ - * /)

n1 = 3
n2 = 31
n3 = n1 + n2
print("n3 =" , n3)
n4 = n2 - n1
print("n4 =", n4)
n5 = n1 * n2
print("n5 =", n5)
n6 = 10/5
print("n6 =", n6)

------>

n3 = 34
n4 = 28
n5 = 93
n6 = 2.0

2.求幂(**)、取余(%)

n1 = 3
n2 = n1 ** n1
print("n2 = " , n2)
n3 = 33%7
print("n3 = " , n3)

----->

n2 = 27
n3 = 5

3.只求商(//),不输出余数

n3 = 33//7
print("n3 = " , n3)

----->n3 =  4

posted @ 2018-11-28 16:47  醉墨寒香  阅读(495)  评论(0)    收藏  举报