#Leetcode# 33. Search in Rotated Sorted Array

https://leetcode.com/problems/search-in-rotated-sorted-array/

 

Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.

(i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]).

You are given a target value to search. If found in the array return its index, otherwise return -1.

You may assume no duplicate exists in the array.

Your algorithm's runtime complexity must be in the order of O(log n).

Example 1:

Input: nums = [4,5,6,7,0,1,2], target = 0
Output: 4

Example 2:

Input: nums = [4,5,6,7,0,1,2], target = 3
Output: -1

代码:

class Solution {
public:
    int search(vector<int>& nums, int target) {
        int n = nums.size();
        map<int, int> mp;
        mp.clear();
        for(int i = 0; i < n; i ++)
            mp[nums[i]] = i;
        
        sort(nums.begin(), nums.end());
        int l = 0, r = n - 1;
        int mid;
        while(l <= r) {
            mid = (r - l) / 2 + l;
            if(nums[mid] == target) return mp[nums[mid]];
            else if(nums[mid] > target) r = mid - 1;
            else l = mid + 1;
        }
        return -1;
    }
}; 

惊险!0.93%

 

posted @ 2018-11-22 13:21  丧心病狂工科女  阅读(98)  评论(0编辑  收藏  举报