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The following example shows how to write a custom IFormatProvider which you can use in methodString.Format(I­FormatProvider, …).

This formatter formats doubles to 3 decimal places with a dot separator.

[C#]

public class DoubleFormatter : IFormatProvider, ICustomFormatter
{
// always use dot separator for doubles
private CultureInfo enUsCulture = CultureInfo.GetCultureInfo("en-US");
 
public string Format(string format, object arg, IFormatProvider formatProvider)
{
// format doubles to 3 decimal places
return string.Format(enUsCulture, "{0:0.000}", arg);
}
 
public object GetFormat(Type formatType)
{
return (formatType == typeof(ICustomFormatter)) ? this : null;
}
}

Having this formatter, we can use it like this:

[C#]

double width = 15.77555;
double height = 12.8497979;
Console.WriteLine(string.Format(new DoubleFormatter(), "w={0} h={1}", width, height));

Output:

w=15.776 h=12.850

So now we have a reusable format for doubles – 3 decimal places with dot separator. That is nice, but this formatter is very simple – it formats everything (eg. DateTime) as „0:000“. This is a fast version if you know that you will only use it for formatting lots of doubles.

The real version should look like this:

[C#]

public class DoubleFormatter : IFormatProvider, ICustomFormatter
{
// always use dot separator for doubles
private CultureInfo enUsCulture = CultureInfo.GetCultureInfo("en-US");
 
public string Format(string format, object arg, IFormatProvider formatProvider)
{
if (arg is double)
{
if (string.IsNullOrEmpty(format))
{
// by default, format doubles to 3 decimal places
return string.Format(enUsCulture, "{0:0.000}", arg);
}
else
{
// if user supplied own format use it
return ((double)arg).ToString(format, enUsCulture);
}
}
// format everything else normally
if (arg is IFormattable)
return ((IFormattable)arg).ToString(format, formatProvider);
else
return arg.ToString();
}
 
public object GetFormat(Type formatType)
{
return (formatType == typeof(ICustomFormatter)) ? this : null;
}
}

Example:

[C#]

Console.WriteLine(string.Format(new DoubleFormatter(),
"Numbers {0} and {1:0.0}. Now a string {2}, a number {3}, date {4} and object: {5}",
1.234567, -0.57123456, "Hi!", 5, DateTime.Now, new object()));

Output:

Numbers 1.235 and -0.6. Now a string Hi!, a number 5, date 12.6.2009 17:11:35
and object: System.Object

Other examples with custom formatters can be found in MSDN. See example with formatter for 12-digit account numbers (12345–678–9012) or example with binary, octal, and hexadecimal formatter.

IFormatProvider for Numbers [C#]

http://www.csharp-examples.net/iformatprovider-numbers/

This example shows how to convert float to string and string to float using IFormatProvider. To get IFormatProvider you need to get CultureInfo instance first.

Get invariant or specific CultureInfo

Invariant culture is a special type of culture which is culture-insensitive. You should use this culture when you need culture-independent results, e.g. when you format or parse values in XML file. The invariant culture is internally associated with the English language. To get invariantCultureInfo instance use static property CultureInfo.In­variantCulture.

To get specific CultureInfo instance use static method CultureInfo.Get­CultureInfo with the specific culture name, e.g. for the German language CultureInfo.GetCultureInfo("de-DE").

Format and parse numbers using the IFormatProvider

Once you have the CultureInfo instance use property CultureInfo.Num­berFormat to get anIFormatProvider for numbers (the NumberFormatInfo object)

[C#]

// format float to string
float num = 1.5f;
string str = num.ToString(CultureInfo.InvariantCulture.NumberFormat); // "1.5"
string str = num.ToString(CultureInfo.GetCultureInfo("de-DE").NumberFormat); // "1,5"

[C#]

// parse float from string
float num = float.Parse("1.5", CultureInfo.InvariantCulture.NumberFormat);
float num = float.Parse("1,5", CultureInfo.GetCultureInfo("de-DE").NumberFormat);
posted on 2014-12-26 15:01  Gu  阅读(...)  评论(...编辑  收藏